Problem 48
Question
For the following exercises, simplify each expression. \(q^{\frac{3}{2}} \sqrt{63 p}\)
Step-by-Step Solution
Verified Answer
The simplified expression is \(3q^{\frac{3}{2}} \sqrt{7p}\).
1Step 1: Simplify the Square Root
The expression inside the square root is \( \sqrt{63p} \). Let's simplify this by factoring out the square and any perfect squares in 63: \( 63 = 9 \times 7 \), and \( \sqrt{9} = 3 \). So, \( \sqrt{63p} = \sqrt{9 \times 7p} = 3\sqrt{7p} \).
2Step 2: Recombine the Expression
Now, combine this with the \( q^{\frac{3}{2}} \): \( q^{\frac{3}{2}} \sqrt{63p} = q^{\frac{3}{2}} \cdot 3\sqrt{7p} \).
3Step 3: Simplify the Coefficients
We can simplify the expression by multiplying the coefficients and leaving the variable expressions separate: \( 3q^{\frac{3}{2}} \sqrt{7p} \).
Key Concepts
Square RootsExponentsFactoring
Square Roots
When working with square roots, you're dealing with numbers or expressions raised to the power of 1/2. Square roots help us find a number which, when multiplied by itself, gives the original number. In algebra, simplifying square roots often requires breaking them down into factors.
To simplify, identify pairs of factors from the original number inside the root. Take out any perfect square factors, as these can be written as base values outside of the square root.
To simplify, identify pairs of factors from the original number inside the root. Take out any perfect square factors, as these can be written as base values outside of the square root.
- For example, consider \( \sqrt{63} \): Since \( 63 = 9 \times 7 \), and \( \sqrt{9} = 3 \), we have \( \sqrt{63} = 3\sqrt{7} \).
- This means 9 is a perfect square factor, simplifying our task of reducing the expression.
Exponents
Exponents are all about repeated multiplication. They show how many times a number, known as the base, is multiplied by itself. Fractional exponents, like \( q^{\frac{3}{2}} \), are an extension of this concept—combining power and root operations.
The fractional exponent \( \frac{3}{2} \) represents a base raised to the third power and taking the square root of the result. Mathematically, this can be expressed in parts:
The fractional exponent \( \frac{3}{2} \) represents a base raised to the third power and taking the square root of the result. Mathematically, this can be expressed in parts:
- First, raise the base to the power of 3, \( q^3 \).
- Second, apply the square root: \( \sqrt{q^3} \).
Factoring
Factoring is the process of breaking down numbers or expressions into their multiplicative components. This algebraic technique is key to simplifying complex expressions.
Start by identifying numbers and variables that can be divided into smaller parts or factors. Utilize the concept of prime factorization where you express numbers as a product of primes.
Start by identifying numbers and variables that can be divided into smaller parts or factors. Utilize the concept of prime factorization where you express numbers as a product of primes.
- For instance, \( 63 = 3 \times 3 \times 7 \), which makes the factoring \( 9 \times 7 \), where 9 is a perfect square.
- In the expression \( \sqrt{63p} \), we broke it down to \( 3\sqrt{7p} \), neatly separating constants from radicals and simplifying the square root term.
Other exercises in this chapter
Problem 48
For the following exercises, factor the polynomials. \(9 y(3 y-13)^{\frac{1}{5}}-2(3 y-13)^{\frac{6}{5}}\)
View solution Problem 48
For the following exercises, multiply the polynomials. \((9 m+4 n-1)(2 m+8)\)
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The Gross Domestic Product (GDP) for the United States in the first quarter of 2014 was \(\$ 1.71496 \times 10^{13}\). Rewrite the GDP in standard notation.
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For the following exercises, simplify the expression. \(18 y-2(1+7 y)\)
View solution