Problem 48
Question
For the following exercises, express the equations in slope intercept form (rounding each number to the thousandths place). Enter this into a graphing calculator as \(Y 1,\) then adjust the ymin and ymax values for your window to include where the y-intercept occurs. State your ymin and ymax values. $$ 4,500 x-200 y=9,528 $$
Step-by-Step Solution
Verified Answer
Equation: \( y = 22.5x - 47.64 \). Set ymin = -50 and ymax = 10.
1Step 1: Rearrange the Equation into Slope-Intercept Form
The slope-intercept form of a line is given by \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. Start by arranging the given equation, \( 4500x - 200y = 9528 \), to solve for \( y \). First, subtract \( 4500x \) from both sides: \(-200y = -4500x + 9528\).
2Step 2: Solve for y
Now, divide every term by \(-200\) to solve for \( y \): \( y = \frac{4500}{200}x - \frac{9528}{200} \). Simplifying these fractions gives \( y = 22.5x - 47.64 \).
3Step 3: Input Equation into Graphing Calculator
Enter the equation \( y = 22.5x - 47.64 \) into your graphing calculator as \( Y_1 \). This is your equation in slope-intercept form.
4Step 4: Determine Y-Intercept for Graphing
The y-intercept is \(-47.64\), so you should ensure your calculator can display this point on the graph.
5Step 5: Set Ymin and Ymax
Adjust the graphing calculator settings to include the y-intercept. Set your \( ymin \) to a value a bit lower than \(-47.64\), such as \(-50\). Choose \( ymax \) to accommodate the rest of the line; a covering range could be \( 10 \).
Key Concepts
Graphing EquationsLinear EquationsY-Intercept
Graphing Equations
Graphing equations is a visual way to understand the relationships between variables. It involves plotting points on a graph that show the relationship defined by an equation. By graphing an equation, you can see how changing one variable affects another. For linear equations, which form a straight line, understanding graphing allows you to visually perceive the slope and y-intercept.
- Start by identifying the equation you need to graph, which in step 2 of our solution is given as \( y = 22.5x - 47.64 \).
- Using a graphing calculator or plotting manually, you plot the line based on the slope and y-intercept from the equation.
- The plotted line will reveal how \( x \) and \( y \) are related through the slope-intercept form equation.
Linear Equations
Linear equations represent one of the simplest forms of mathematical expressions. They consist of two variables without any exponents or powers, forming a straight line when graphed. The general form of a linear equation is often given as \( ax + by = c \), which can be rearranged to the slope-intercept form.
- The exercise we worked on starts with the equation \( 4500x - 200y = 9528 \).
- By rearranging and simplifying, we obtained \( y = 22.5x - 47.64 \).
- The equation showcases a linear relationship between \( x \) and \( y \).
Y-Intercept
The y-intercept is a key feature of the slope-intercept form of a linear equation. It is the point where the line crosses the y-axis, meaning the value of \( y \) when \( x = 0 \). This gives us valuable information on the starting point in many practical applications.
- In the equation \( y = 22.5x - 47.64 \), the y-intercept is \(-47.64\).
- When graphing, you need to ensure the y-intercept is displayed within your chosen graph window.
- Setting values such as \( ymin = -50 \) and \( ymax = 10 \) accommodates this y-intercept well on a graphing calculator.
Other exercises in this chapter
Problem 48
For the following exercises, evaluate the expressions, writing the result as a simplified complex number. $$ \frac{1}{i^{11}}-\frac{1}{i^{21}} $$
View solution Problem 48
For the following exercises, solve for the given variable in the formula. After obtaining a new version of the formula, you will use it to solve a question. The
View solution Problem 48
For the following exercises, use your graphing calculator to input the linear graphs in the \(Y=\) graph menu. After graphing it, use the \(2^{\text {nd }}\) CA
View solution Problem 49
For the following exercises, write the interval in set-builder notation. [-3,5)
View solution