Problem 48
Question
For exercises \(45-48\), the formula \(R=\frac{U F}{P}\) describes the glomular filtration rate by a kidney \(R\). Is the relationship of the given variables a direct variation or an inverse variation? $$ R \text { and } P \text { are constant; the relationship of } U \text { and } F \text {. } $$
Step-by-Step Solution
Verified Answer
It's a direct variation between \( U \) and \( F \).
1Step 1: Understand the Given Formula
The given formula is \( R = \frac{UF}{P} \), where \(R\), \(U\), \(F\), and \(P\) represent different variables related to the glomular filtration rate by a kidney.
2Step 2: Identify Constant Variables
According to the problem, \(R\) and \(P\) are constant. Therefore, we need to examine the relationship between \(U\) and \(F\).
3Step 3: Isolate the Relationship of U and F
Rewrite the formula to isolate the relationship between \(U\) and \(F\): \( R = \frac{UF}{P} \). Since \(R\) and \(P\) are constants, let \(C = \frac{P}{R} \), which leads to \( U = CF \).
4Step 4: Determine the Type of Variation
Since \(U = CF\), \(U\) is directly proportional to \(F\). This means that if \(F\) increases, \(U\) also increases, and if \(F\) decreases, \(U\) decreases as well.
Key Concepts
glomular filtration ratedirect variationproportionality
glomular filtration rate
The glomular filtration rate (GFR) is a key measure used to evaluate kidney function. It helps determine how well the kidneys are filtering waste from the blood. The formula used in the exercise is: \( R = \frac{UF}{P} \), where:
- \( R \) represents the GFR.
- \( U \) stands for the urine concentration of a substance.
- \( F \) represents the flow rate of urine.
- \( P \) is the plasma concentration of the same substance.
direct variation
Direct variation describes a relationship where one variable changes directly with another. In our exercise, when we said \( R \) and \( P \) are constants, we looked at the relationship between \( U \) and \( F \). With these constants, the relationship can be simplified as follows: Since \( R \) and \( P \) are constants, let’s rewrite the formula: \( R = \frac{UF}{P} \). To isolate the relationship between \( U \) and \( F \), rewrite it as: \( U = C F \) where \( C = \frac{P}{R} \) is a constant. This equation tells us that \( U \) varies directly with \( F \). What does this mean? It means:
- If \( F \) increases, \( U \) also increases.
- If \( F \) decreases, \( U \) decreases too.
proportionality
Proportionality is a fundamental concept in mathematics and physics. It describes the relationship between two quantities, where one quantity is a constant multiple of the other. In terms of the GFR formula given, we observe proportionality between \( U \) and \( F \). This relationship can be expressed mathematically as \( U = k F \), where \( k \) is a constant of proportionality. Important points about proportionality:
- The graph of proportional relationships is a straight line through the origin.
- In direct proportionality, as one quantity increases, the other quantity also increases by the same factor.
- The constant of proportionality can give us insight into how much one variable changes in relation to another.
Other exercises in this chapter
Problem 47
For exercises 39-82, simplify. $$ \frac{8 a b}{21 c^{2}} \div \frac{2 a^{2}}{3 c} $$
View solution Problem 47
For exercises 1-66, simplify. $$ \frac{y^{2}+11 y+28}{y^{2}-2 y-63} $$
View solution Problem 48
For exercises 43-58, (a) solve. (b) check. $$ \frac{4}{a+6}=\frac{9}{a-4} $$
View solution Problem 48
For exercises \(25-68\), evaluate or simplify. $$ \frac{\frac{3}{x+1}+\frac{1}{x-2}}{\frac{1}{x+1}-\frac{4}{x-2}} $$
View solution