Problem 48
Question
Find the polar equation of the conic with focus at the origin and the given eccentricity and directrix. Directrix: \(x=-1 ; e=1\)
Step-by-Step Solution
Verified Answer
The polar equation is \( r = \frac{1}{1 + \cos\theta} \).
1Step 1: Identify Conic Type
The eccentricity is given as \( e = 1 \). An eccentricity of 1 indicates that the conic is a parabola.
2Step 2: Use the Polar Equation of a Parabola
The polar equation of a conic with focus at the origin and given directrix is \( r = \frac{ed}{1 + e\cos\theta} \) when the directrix is vertical. Since \( e = 1 \), substitute these into the formula.
3Step 3: Express the Directrix
The directrix given is \( x = -1 \). For the equation, \( d = 1 \) as the directrix distance to the pole (origin) is 1 unit away in the negative x-direction. This implies we will substitute \( d = 1 \) into the formula.
4Step 4: Substitute Values into Polar Equation
Substituting \( e = 1 \) and \( d = 1 \) into the equation \( r = \frac{ed}{1 + e\cos\theta} \) gives: \[ r = \frac{1 \cdot 1}{1 + 1 \cos\theta} = \frac{1}{1 + \cos\theta} \].
5Step 5: Verify and Simplify the Result
Check that the equation is correct for a parabola with a directrix at \( x = -1 \). The derived equation \( r = \frac{1}{1 + \cos\theta} \) is indeed the representation of a parabola centered at the pole with the specified directrix.
Key Concepts
EccentricityParabolaDirectrixFocusConic Sections
Eccentricity
Eccentricity is a fundamental concept in the study of conic sections. It determines the shape of the conic: the value of the eccentricity, denoted as \( e \), helps identify whether the conic is a circle, ellipse, parabola, or hyperbola. Here's what you need to know about different conic sections based on eccentricity:
- If \( e = 0 \), the conic is a circle.
- For \( 0 < e < 1 \), it is an ellipse.
- An eccentricity of \( e = 1 \) characterizes a parabola.
- If \( e > 1 \), the conic is a hyperbola.
Parabola
A parabola is a unique type of conic section that has an eccentricity \( e = 1 \). It is defined as the set of all points equidistant from a point known as the focus, and a line called the directrix.A polar equation for a parabola can be derived when it's described in terms of a radial distance \( r \) and an angle \( \theta \), with its focus located at the origin. The general form of the polar equation is: \[ r = \frac{ed}{1 + e\cos\theta} \].For the exercise, we considered a parabola with directrix perpendicular to the polar axis.The radial distance reflects how the conic section changes as the angle \( \theta \) varies, showing symmetry typical of a parabola.
Directrix
The directrix is a crucial element when dealing with conic sections, as it helps define their shape.It is a fixed line that, together with the focus, determines the position and curvature of the conic.In a parabola, each point on the curve is equidistant from the focus and the directrix.
- For our exercise, the directrix is given as \( x = -1 \).
- This means it's a vertical line, 1 unit away from the origin in the negative x-direction.
Focus
In conic sections, the focus is a key point from which distances are measured to define the curve.For a parabola, the focus is not just any point but the point at which distances are equidistant to both it and the directrix.
- In the exercise, the focus is positioned at the origin in polar coordinates, \((0,0)\).
- This simplified the derivation of the polar equation of the conic.
Conic Sections
Conic sections arise from the intersection of a plane with a double-napped cone.This intersection can produce various shapes like circles, ellipses, parabolas, and hyperbolas, each being uniquely characterized by its eccentricity.The nature of conic sections lays the groundwork for broader mathematical fields and applications, emphasizing their wide relevance.
- The parabola, characterized by \( e = 1 \), plays a vital role in fields like physics, engineering, and nature.
- Ellipses and hyperbolas also have important real-world applications, including orbits of planets and hyperbolic geometry.
Other exercises in this chapter
Problem 47
Given information about the graph of the hyperbola, find its equation. Vertices at \((1,1)\) and \((11,1)\) and one focus at \((12,1)\)
View solution Problem 48
For the following exercises, find the polar equation of the conic with focus at the origin and the given eccentricity and directrix. Directrix: \(x=-1 ; e=1\)
View solution Problem 48
For the following exercises, find the equation of the parabola given information about its graph. Vertex is (-2,3)\(;\) directrix is \(x=-\frac{7}{2},\) focus i
View solution Problem 48
For the following exercises, use the given information about the graph of each ellipse to determine its equation. Center at the origin, symmetric with respect t
View solution