Problem 48
Question
Find each product. $$\left(5 x^{2}-3\right)^{2}$$
Step-by-Step Solution
Verified Answer
The product of \((5x^2 - 3)^2\) is \(25x^4 - 30x^2 + 9\).
1Step 1: Identify 'a' and 'b'
In the expression \( (5x^2 - 3)^2 \), 'a' is \(5x^2\) and 'b' is \(3\). We will substitute these values into the formula \((a - b)^2 = a^2 - 2ab + b^2 \)
2Step 2: Substitute 'a' and 'b' in the formula
On substituting \(a = 5x^2\) and \(b = 3\) in the formula we get \((5x^2 - 3)^2 = (5x^2)^2 - 2*5x^2*3 + 3^2 \)
3Step 3: Solve the resulting expression
Now solve the expression. So, \( (5x^2)^2 = 25x^4 \), \( 2*5x^2*3 = 30x^2 \), and \( 3^2 = 9 \). Thus, \((5x^2 - 3)^2 = 25x^4 - 30x^2 + 9 \)
Other exercises in this chapter
Problem 48
Factor the difference of two squares. $$ 81 x^{4}-1 $$
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Rationalize the denominator. $$\frac{\sqrt{7}}{\sqrt{3}}$$
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Add or subtract as indicated. $$\frac{x+3}{x-3}+\frac{x-3}{x+3}$$
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Simplify each exponential expression in Exercises 23–64. $$\left(-5 x^{4} y\right)\left(-6 x^{7} y^{11}\right)$$
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