Problem 48
Question
Factor the expression. $$ 4 n^{2}-64 $$
Step-by-Step Solution
Verified Answer
The factored form of the quadratic expression \(4n^{2}-64\) is \((2n+8)(2n-8)\).
1Step 1: Identify the Square Roots
Identify the square roots of each term in the expression. The square root of \(4n^{2}\) is \(2n\) and the square root of \(64\) is \(8\). So, the expression \(4n^{2}-64\) is equivalent to \((2n)^{2} - (8)^{2}\).
2Step 2: Apply Difference of Squares Formula
Applying a difference of squares formula, \((a)^{2} - (b)^{2} = (a+b)(a-b)\), where, in this case, \(a\) is \(2n\) and \(b\) is \(8\). This leads to \((2n+8)(2n-8)\).
3Step 3: Simplify the Expressions
Simplify the expressions in both brackets. The simplified expression becomes \((2n+8)(2n-8)\).
Key Concepts
Difference of SquaresQuadratic ExpressionsPolynomials
Difference of Squares
When it comes to factoring, the difference of squares is a fundamental concept. It refers to an expression that involves two squared terms separated by a minus sign. The general formula is
In our exercise, the expression \(4n^2 - 64\) is a classic example. Here,
- \(a^2 - b^2 = (a + b)(a - b)\)
In our exercise, the expression \(4n^2 - 64\) is a classic example. Here,
- \(4n^2\) can be expressed as \((2n)^2\)
- \(64\) can be expressed as \((8)^2\)
Quadratic Expressions
A quadratic expression is a polynomial expression of degree 2, meaning the highest exponent of the variable is 2. These expressions typically take the form
In the given exercise, \(4n^2 - 64\) might not appear as a conventional quadratic expression due to its missing linear (\(bx\)) term. However, it still qualifies as quadratic since the highest power of \(n\) is 2.
Factoring quadratic expressions can solve equations or find roots more easily. Recognizing patterns such as the difference of squares speeds up this process significantly. By factoring, we've transformed the quadratic \(4n^2 - 64\) into the product form \((2n + 8)(2n - 8)\), simplifying the expression.
- \(ax^2 + bx + c\)
In the given exercise, \(4n^2 - 64\) might not appear as a conventional quadratic expression due to its missing linear (\(bx\)) term. However, it still qualifies as quadratic since the highest power of \(n\) is 2.
Factoring quadratic expressions can solve equations or find roots more easily. Recognizing patterns such as the difference of squares speeds up this process significantly. By factoring, we've transformed the quadratic \(4n^2 - 64\) into the product form \((2n + 8)(2n - 8)\), simplifying the expression.
Polynomials
Polynomials are algebraic expressions consisting of variables and coefficients. These expressions are structured through addition, subtraction, and multiplication operations, often arranged in ascending order of degrees.
The provided expression, \(4n^2 - 64\), is classified as a polynomial. Although minimal in complexity, it still highlights the essential polynomial pattern.
The provided expression, \(4n^2 - 64\), is classified as a polynomial. Although minimal in complexity, it still highlights the essential polynomial pattern.
- This particular polynomial features two terms: \(4n^2\) and \(-64\).
- The degree of the term \(n\) partially defines its categorization.
Other exercises in this chapter
Problem 48
Complete the statement using \(,\) or \(=\). \(0.23 ? \frac{23}{100}\)
View solution Problem 48
Plot and label the ordered pairs in a coordinate plane. $$ A(2,-5), B(2,4), C(-3,0) $$
View solution Problem 48
Solve the quadratic equation. $$ x^{2}+2 x-11=0 $$
View solution Problem 48
Solve the equation. Write the solutions as integers if possible. Otherwise, write them as radical expressions. $$ 16+x^{2}=64 $$
View solution