Problem 48
Question
Exer. 47-52: Sketch the graph of \(f\). $$ f(x)= \begin{cases}-1 & \text { if } x \text { is an integer } \\ -2 & \text { if } x \text { is not an integer }\end{cases} $$
Step-by-Step Solution
Verified Answer
The graph has dots at \(y = -1\) for integer \(x\) and a line at \(y = -2\) for non-integer \(x\).
1Step 1: Understanding the Function Definition
The function \( f(x) \) is defined as a piecewise function. It takes two different values: \(-1\) when \(x\) is an integer and \(-2\) when \(x\) is not an integer.
2Step 2: Identifying Integer Values
List or note all integer values of \(x\) within the domain you're considering. For a more general graph, integers like -3, -2, -1, 0, 1, 2, 3, etc., should be considered.
3Step 3: Plotting Values for Integer Inputs
For each integer \(x\), plot a point at \((x, -1)\). These points will form a horizontal line at \(y = -1\) but only where \(x\) is an integer. This represents the first case in our piecewise function.
4Step 4: Plotting Values for Non-Integer Inputs
For all non-integer values of \(x\), plot a point at \((x, -2)\). This forms a continuous horizontal line at \(y = -2\) for all non-integer \(x\). This represents the second case of the piecewise function.
5Step 5: Finalizing and Sketching the Graph
Combine the plotted points into a coherent graph. The graph consists of separate horizontal point-lined segments at \(y = -1\) for integer \(x\) and a solid horizontal line at \(y = -2\) for non-integer \(x\). Make sure the points for \(y = -1\) are clear and distinct on this graph.
Key Concepts
GraphingInteger ValuesNon-Integer Values
Graphing
A piecewise function can be visualized using graphing, which helps us easily see the behavior of the function over different sections of its domain. When graphing a piecewise function like \(f(x)\), we first identify the different cases provided in the function's definition. Each case will correspond to a specific line or point on the graph. In our case, for \(f(x)\), we have two different horizontal lines:
- A horizontal line at \(y = -1\), corresponding to integer values of \(x\).
- A horizontal line at \(y = -2\), for non-integer values of \(x\).
Integer Values
Integer values are specific values of \(x\) where the function \(f(x) = -1\). Each integer leads to one plot point on the graph located at \((x, -1)\). Common integers like \(-3, -2, -1, 0, 1, 2, 3\) are easy examples. When we plot these points, they collectively appear as a dotted horizontal line along \(y = -1\).
- Identify integers within the chosen domain.
- Plot exactly at these integers, avoiding any fractional or decimal numbers.
- Use distinct dots or circles to indicate these discrete points.
Non-Integer Values
Non-integer values, such as fractions and decimals, correspond to the second case in the function \(f(x) = -2\). For any value of \(x\) that is not an integer, the function remains constant at \(y = -2\).
This results in a solid horizontal line at \(y = -2\), representing all non-integer inputs such as \(x = 0.5, x = 1.8\), etc.
This results in a solid horizontal line at \(y = -2\), representing all non-integer inputs such as \(x = 0.5, x = 1.8\), etc.
- Focus on values that aren't whole numbers, even if they are complex like square roots or irrational numbers.
- The line formed by these points is seamless and continuous, clearly distinguishing it from the dotted one for integer values.
- Ensuring non-integers cover the gaps left by the integers helps complete the visual representation of the piecewise function.
Other exercises in this chapter
Problem 47
Exer. 47-48: Simplify the difference quotient $$ \frac{f(2+h)-f(2)}{h} \text { if } h \neq 0 . $$ $$ f(x)=x^{2}-3 x $$
View solution Problem 47
Exer. 47-56: Find the center and radius of the circle with the given equation. $$ x^{2}+y^{2}-4 x+6 y-36=0 $$
View solution Problem 48
The diagonal \(d\) of a cube is the distance between two opposite vertices. Express \(d\) as a function of the edge \(x\) of the cube. (Hint: First express the
View solution Problem 48
In the \(1940 \mathrm{~s}\), the human cannonball stunt was performed regularly by Emmanuel Zacchini for The Ringling Brothers and Barnum \& Bailey Circus. The
View solution