Problem 48
Question
Divide as indicated. $$\frac{y^{2}-2 y}{15} \div \frac{y-2}{5}$$
Step-by-Step Solution
Verified Answer
The result of the division \( \frac{y^{2}-2 y}{15} \div \frac{y-2}{5} \) is \( \frac{y}{3} \).
1Step 1: Convert into Multiplication
Convert the division operation into multiplication, by finding the reciprocal of \( \frac{y-2}{5} \). The reciprocal of a fraction is obtained by reversing (or 'flipping') the positions of the numerator and the denominator. This yields: \( \frac{y^{2}-2 y}{15} \times \frac{5}{y-2} \).
2Step 2: Simplify Multiplication
Next, cancel out the common factors between the numerators and denominators. Here, on splitting \( y^{2}-2 y \) as \( y(y-2) \), we find that \( y-2 \) common in the numerator of the first fraction and the denominator of the second fraction. The number 15 in the denominator of the first fraction and 5 in the numerator of the second fraction also have a common factor of 5. Therefore, cancel out the common factors to get: \( \frac{y \times 1}{3 \times 1} \), which simplifies to \( \frac{y}{3} \).
3Step 3: Final Solution
The simplified form of the given expression after performing the division operation is \( \frac{y}{3} \). This is the final answer. Proceed to write this in final solution.
Other exercises in this chapter
Problem 48
Simplify complex rational expression. \(\frac{1}{1+\frac{1}{1+\frac{1}{2}}}\)
View solution Problem 48
Add or subtract as indicated. Simplify the result, if possible. $$\frac{y}{y-5}-\frac{y-5}{y}$$
View solution Problem 48
Solve or simplify, whichever is appropriate. $$\frac{x^{2}+4 x-2}{x^{2}-2 x-8}=1+\frac{4}{x-4}$$
View solution Problem 49
denominators are opposites, or additive inverses. Add or subtract as indicated. Simplify the result, if possible. $$\frac{6}{x-1}-\frac{5}{1-x}$$
View solution