Problem 48
Question
Determine which of the numbers in the set are (a) natural numbers, (b) integers, (c) rational numbers, and (d) irrational numbers. $$\left\\{-6, \frac{7}{4}, 2,1, \sqrt{49},-8, \frac{4}{3}\right\\}$$
Step-by-Step Solution
Verified Answer
The natural numbers in the set are 2, 1, and 7 (\(\sqrt{49}\)). The integers in the set are -6, 2, 1, 7, and -8. The rational numbers are -6, \(\frac{7}{4}\), 2, 1, 7, -8, and \(\frac{4}{3}\). The set does not include any irrational numbers.
1Step 1: Identifying Natural Numbers
Natural numbers are counting numbers starting from 1. In the given set, the natural numbers are \(2\) and \(1\). The number \(\sqrt{49}\) is also a natural number since square root of \(49\) is \(7\), which is a natural number.
2Step 2: Identifying Integers
Integers include all natural numbers, zero, and their negatives. From the set, therefore, the integers are \(-6\), \(2\), \(1\), \(\sqrt{49}\) (which is \(7\)), and \(-8\). Note that the fractional numbers, namely \(\frac{7}{4}\) and \(\frac{4}{3}\), are not integers since they are not whole numbers.
3Step 3: Identifying Rational Numbers
Rational numbers are numbers that can be written as a fraction where the denominator is not zero. This means all integers are rational (because they can be written as the integer divided by \(1\)), and any fraction with non-zero denominator is also a rational number. Therefore, all numbers in the set except for one are rational: \(-6\), \(\frac{7}{4}\), \(2\), \(1\), \(\sqrt{49}\), \(-8\), and \(\frac{4}{3}\).
4Step 4: Identifying Irrational Numbers
Irrational numbers cannot be expressed as fractions and their decimal expansion neither terminates nor become periodic. In the given set, however, all numbers can be written as a fraction or terminate as decimal; hence, there are no irrational numbers.
Key Concepts
Natural NumbersIntegersRational NumbersIrrational Numbers
Natural Numbers
Natural numbers are the simplest and most straightforward type of numbers. They are the numbers you use for counting. Think of how you count your fingers or toys - these are the natural numbers. This means they start at 1 and go up like 2, 3, 4, and so on. Importantly, they do not include zero or negative numbers.
In the given exercise set, let's identify the natural numbers:
In the given exercise set, let's identify the natural numbers:
- The number 2 is a natural number, simply because you count it.
- The number 1 is also a natural number for the same reason.
- Then there's \( \sqrt{49} \). When you solve this, you get 7, which is undoubtedly a natural number!
Integers
Integers expand on the idea of natural numbers by including zero and negative numbers. This inclusion makes integers a broader category. To grasp integers, imagine a number line that stretches infinitely in both directions and includes not just positive numbers, but also negative numbers and zero.
From the given set of numbers, these are the integers:
From the given set of numbers, these are the integers:
- -6 is an integer because it continues on this number line below zero.
- 2 and 1 remain integers, as they are already natural numbers and thus fit into integers, too.
- \( \sqrt{49} \) is 7, and 7 is an integer as well.
- -8 is, like -6, an integer, falling on the negative side of the number line.
Rational Numbers
Rational numbers are where the fraction fun begins! They're considered rational because they are ratios (or fractions) of integers. Another important fact about rational numbers is that their decimal expansions either end or repeat.
For example:
For example:
- A simple integer like -6 can be considered a rational number since you can express it as \( \frac{-6}{1} \), with 1 as the denominator.
- Fractions like \( \frac{7}{4} \) and \( \frac{4}{3} \) are already in quintessential rational form (number over a number, denominator isn't zero).
- The numbers 2 (\( \frac{2}{1} \)), 1 (\( \frac{1}{1} \)), and 7 (since it's \( \sqrt{49} \); \( \frac{7}{1} \)) fit as rational numbers too.
- Finally, -8 can slide right into the rational zone as \( \frac{-8}{1} \).
Irrational Numbers
Irrational numbers live on a number line too, but they come with a tricky twist of being impossible to fully write down as fractions of integers. Their decimal versions aren't neat or repeating.
Explore examples to clarify:
Explore examples to clarify:
- A number like \( \pi \) or \( \sqrt{2} \) would be deemed irrational for its non-repeating, non-ending decimal form.
- In contrast, our set lacks such endlessly diverse numbers, indicating no entries are irrational.
Other exercises in this chapter
Problem 47
Solve the equation and check your solution. $$5(3-x)=x-12$$
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Solve and graph the inequality. $$\frac{y}{4}-\frac{5}{8}
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Solve the equation. Round your answer to two decimal places. $$4-0.3 x=1$$
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Solve the equation and check your solution. $$12-w=-2(3 w-1)$$
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