Problem 48
Question
Compute the exact square root. \(\sqrt{\frac{49}{36}}\)
Step-by-Step Solution
Verified Answer
The exact square root is \( \frac{7}{6} \).
1Step 1: Separate the Fraction
Start by expressing the square root of the fraction as a fraction of square roots. That is, \( \sqrt{\frac{49}{36}} = \frac{\sqrt{49}}{\sqrt{36}} \).
2Step 2: Calculate the Square Root of the Numerator
The numerator of the fraction is 49, which is a perfect square. Therefore, \( \sqrt{49} = 7 \).
3Step 3: Calculate the Square Root of the Denominator
The denominator of the fraction is 36, which is also a perfect square. As such, \( \sqrt{36} = 6 \).
4Step 4: Form the Fraction
With the results from the previous two steps, form the fraction for the square root of the original fraction: \( \frac{7}{6} \). This is the exact square root of \( \frac{49}{36} \).
Key Concepts
Perfect SquaresFractionsNumerator and Denominator Manipulation
Perfect Squares
Perfect squares are numbers that are the square of an integer. For example, 49 is a perfect square because it is equal to 7 multiplied by itself: 7 × 7 = 49. Understanding perfect squares is crucial when dealing with square roots, as they help simplify calculations significantly.
- Recognizing perfect squares can speed up your calculations.
- They allow you to quickly pinpoint elements in math problems that will have an exact square root.
- You can always find a perfect square by multiplying any integer by itself. In this exercise, both 49 (numerator) and 36 (denominator) are perfect squares.
Fractions
Fractions represent parts of a whole and consist of two components: the numerator and the denominator. In the expression of \[\sqrt{\frac{49}{36}},\]the fraction \(\frac{49}{36}\) has a numerator of 49 and a denominator of 36.
- The fraction line divides these two parts and indicates division.
- A fraction simplifies if both the numerator and the denominator have a common factor.
- Understanding fractions is essential in breaking down more complex mathematical problems into simpler parts, just like separating the square root of each fractional component in the original problem.
Numerator and Denominator Manipulation
Numerator and denominator manipulation are important skills when dealing with fractions, especially when involving operations like square roots. In this exercise, each component of the fraction, 49 and 36, is evaluated separately.
- The numerator (49) is evaluated for its square root independently of the denominator.
- The denominator (36) undergoes the same process; each plays a role in determining the simplified result.
- After finding their roots, the fraction is reassembled into a simplified form.
Other exercises in this chapter
Problem 47
Add or subtract the decimals, as indicated. \(2 .001-4.202\)
View solution Problem 47
Convert the given decimal to a mixed fraction. Do not simplify your answer. 560.453
View solution Problem 48
Solve the equation. \(-7.93+0.01(x+7.9)=14.2\)
View solution Problem 48
Simplify the given expression by first converting the fraction into a terminating decimal. \(-\frac{7}{4}+3.3\)
View solution