Problem 48
Question
An increase in temperature causes most metals to undergo thermal expansion, which means the volume of the metal increases upon heating. How does thermal expansion affect the unit cell length? What is the effect of an increase in temperature on the density of a metal?
Step-by-Step Solution
Verified Answer
Thermal expansion increases the unit cell length and decreases the density of the metal when temperature rises.
1Step 1: Understanding Thermal Expansion
Thermal expansion refers to the phenomenon where the dimensions of a material increase as its temperature rises. For metals, this means that the size of its unit cell, which is the smallest repeating structure in the crystal lattice, will also increase. Thus, an increase in temperature leads to an expansion in unit cell length for the metal.
2Step 2: Applying Thermal Expansion to Unit Cell
When a metal undergoes thermal expansion, the length of each side of the unit cell increases. If the original length of a unit cell at temperature \( T_0 \) is \( a_0 \), at a higher temperature \( T \), the length becomes \( a(T) = a_0 (1 + eta riangle T) \), where \( eta \) is the linear expansion coefficient and \( riangle T = T - T_0 \). This results in a larger unit cell volume.
3Step 3: Calculating Volume Change
The volume of the unit cell \( V \) is given by \( V = a^3 \). Upon expansion, the new volume \( V(T) = [a_0 (1 + eta riangle T)]^3 \), which means the volume increases at a rate dependent on the cube of the expansion of the unit cell length.
4Step 4: Determining the Effect on Density
Density \( \rho \) is defined as mass per unit volume: \( \rho = \frac{m}{V} \). As the volume increases due to thermal expansion but the mass remains constant, the density of the metal decreases with an increase in temperature. This is because \( \rho(T) = \frac{m}{[a_0 (1 + eta riangle T)]^3} \), where the denominator increases with temperature, thereby reducing density.
Key Concepts
Understanding the Unit Cell in MetalsMetal Density and Thermal ExpansionRole of Linear Expansion Coefficient
Understanding the Unit Cell in Metals
In the study of crystallography, the concept of the unit cell is fundamental. A unit cell is the smallest divisible portion of a crystal lattice that retains the overall symmetry and properties of the entire structure. Consider it like a basic building block that repeats in three-dimensional space to form a material.
- Each unit cell is defined by its cell length and cell angles.
- The arrangement of atoms within this unit cell determines the material's properties.
- Thermal expansion depends on how easily the material's atoms can move and the structure of the lattice.
- Despite this increase in unit cell size, the atomic amount per unit cell remains unchanged.
Metal Density and Thermal Expansion
Density is a measure of mass per unit volume. For metals, it's crucial to understand how temperature changes can affect density since this can impact mechanical properties and functionality.
- The density formula: \( \rho = \frac{m}{V} \), where \( m \) is the mass and \( V \) is the volume.
- As temperature rises, metals expand leading to a larger volume \( V \) but the mass \( m \) remains the same.
- The volume becomes larger due to the unit cell expansion, changing density.
- Understanding this concept helps in applications where weight and material strength are crucial.
Role of Linear Expansion Coefficient
The linear expansion coefficient, often represented by \( \alpha \), is a material-specific constant that quantifies how much a material's dimensions change per degree of temperature change. This value is integral when predicting thermal expansion outcomes for precision-required applications.
- The formula for new unit cell dimensions at a higher temperature is: \( a(T) = a_0 (1 + \alpha \Delta T) \).
- Here, \( a_0 \) is the initial dimension, \( \Delta T \) is the temperature change, and \( \alpha \) is the linear expansion coefficient.
- The higher the linear expansion coefficient, the more a metal will expand with temperature increase.
- This coefficient is essential for engineers and designers to prevent issues in thermal expansion scenarios.
Other exercises in this chapter
Problem 46
Indicate whether each statement is true or false: (a) Intermetallic compounds have a fixed composition. (b) Copper is the majority component in both brass and b
View solution Problem 47
Which element or elements are alloyed with gold to make the following types of "colored gold" used in the jewelry industry? For each type, also indicate what ty
View solution Problem 49
State whether each sentence is true or false: (a) Metals have high electrical conductivities because the electrons in the metal are delocalized. (b) Metals have
View solution Problem 50
Imagine that you have a metal bar sitting half in the sun and half in the dark. On a sunny day, the part of the metal that has been sitting in the sun feels hot
View solution