Problem 48
Question
add or subtract as indicated. $$ \frac{x+3}{x-3}+\frac{x-3}{x+3} $$
Step-by-Step Solution
Verified Answer
The simplified expression of \(\frac{x+3}{x-3} + \frac{x-3}{x+3}\) is \(\frac{2x^2+18}{x^2-9}\)
1Step 1: Identify the Lowest Common Denominator
The current denominators of the fractions are \(x-3\) and \(x+3\), their product \( (x-3)(x+3) = x^2 - 9\) would be the least common denominator.
2Step 2: Rewrite the fractions with the common denominator
Rewrite each fraction so that they both have the common denominator \(x^2 - 9\). This gives \(\frac{(x+3)(x+3)}{x^2 - 9} + \frac{(x-3)(x-3)}{x^2 - 9}\)
3Step 3: Simplify the numerators
Simplify the numerators to get \(\frac{x^2+6x+9}{x^2-9} + \frac{x^2-6x+9}{x^2-9}\)
4Step 4: Combine the fractions
As the fractions have the same denominator, they can be combined as follows \(\frac{x^2+6x+9 + x^2-6x+9}{x^2-9}\)
5Step 5: Simplify the combined fraction
Further simplification gives \(\frac{2x^2+18}{x^2-9}\)
Key Concepts
Least Common DenominatorFraction AdditionPolynomial Simplification
Least Common Denominator
In math, when you're adding or subtracting fractions, you need a common baseline to work from, and that's where the Least Common Denominator (LCD) comes in. This is the smallest expression that all denominators can divide into evenly, and it ensures that fractions share the same denominator so they can be easily added or subtracted.
For rational expressions involving variables, finding the LCD might involve factoring.
For rational expressions involving variables, finding the LCD might involve factoring.
- First, always identify the denominators of the given fractions. For example, in the problem we're discussing, \(x-3\) and \(x+3\) are the denominators.
- To get the LCD, multiply these denominators together: \( (x-3)(x+3) = x^2 - 9\).
Fraction Addition
Once you've established the common denominator, it's time to add the fractions. Adding fractions isn't much different from adding numbers, but requires careful adjustment of the numerators because they must share the denominator.
Begin by rewriting each fraction with the newly found least common denominator:
Begin by rewriting each fraction with the newly found least common denominator:
- The first fraction becomes \(\frac{(x+3)(x+3)}{x^2 - 9}\) by multiplying the numerator and denominator by each other's denominator.
- Similarly, the second fraction is rewritten as \(\frac{(x-3)(x-3)}{x^2 - 9}\).
- This results in \(\frac{(x^2+6x+9) + (x^2-6x+9)}{x^2-9}\).
Polynomial Simplification
Simplifying polynomials is what makes the final expression as clean and understandable as possible. To do this, focus on the expressions in the numerators.
In our example, there's a lot of action happening in the numerator that can be tidied up:
The goal of polynomial simplification is to ensure the resulting expression is as straightforward as possible, which facilitates easier interpretation and more efficient calculations.
In our example, there's a lot of action happening in the numerator that can be tidied up:
- After expanding and then adding terms, our numerator is \(x^2 + 6x + 9 + x^2 - 6x + 9\).
- You can immediately combine like terms: \(x^2 + x^2 = 2x^2\), and the linear terms with opposite coefficients, \(6x\) and \(-6x\), cancel each other out.
- The constants add up as \(9 + 9 = 18\).
The goal of polynomial simplification is to ensure the resulting expression is as straightforward as possible, which facilitates easier interpretation and more efficient calculations.
Other exercises in this chapter
Problem 47
Simplify each exponential expression. $$ \left(-9 x^{3} y\right)\left(-2 x^{6} y^{4}\right) $$
View solution Problem 47
True or false. $$-\pi \geq-\pi$$
View solution Problem 48
Factor the difference of two squares. $$81 x^{4}-1$$
View solution Problem 48
Rationalize the denominator. $$ \frac{\sqrt{7}}{\sqrt{3}} $$
View solution