Problem 48
Question
(a) write the repeating decimal as a geometric series and (b) write its sum as the ratio of two integers $$ 0 . \overline{9} $$
Step-by-Step Solution
Verified Answer
The sum of the geometric series represented by the repeating decimal \(0.\overline{9}\) is 1.
1Step 1: Identify the geometric series
The repeating decimal \(0.\overline{9}\) can be represented as a geometric series where the first term (a) is 0.9, the common ratio (r) is 0.1, and n approaches infinity. Therefore, our geometric series becomes: \(0.9 + 0.09 + 0.009 + \ldots\).
2Step 2: Applying the geometric series sum formula
The sum (S) of an infinite geometric series can be calculated using the formula: \( S = \frac{a}{1-r} \), where a is the first term, and r is the common ratio. Substituting our values into this formula, we get: \( S = \frac{0.9}{1 - 0.1} \).
3Step 3: Simplify the sum
Simplifying the equation, we find that: S = 1.
Key Concepts
Repeating DecimalSum of Infinite SeriesCommon Ratio
Repeating Decimal
A repeating decimal is a decimal number that has digits that repeat infinitely. Such numbers can look daunting at first, but they actually follow a neat pattern. For example, consider the repeating decimal \(0.\overline{9}\). This means that the number 9 repeats itself forever after the decimal point.
To express a repeating decimal as a series, we need to identify the pattern of repetition. Once we've identified this pattern, we can write it as a sum of terms in a geometric series. This allows us to understand the repeating decimal in a new way and paves the path for further calculations like finding its sum as a fraction.
To express a repeating decimal as a series, we need to identify the pattern of repetition. Once we've identified this pattern, we can write it as a sum of terms in a geometric series. This allows us to understand the repeating decimal in a new way and paves the path for further calculations like finding its sum as a fraction.
- The repeating part after the decimal is just a series of numbers. In our case, 9 repeats.
- We can summarize the entire series as \(0.9 + 0.09 + 0.009 + \ldots\).
Sum of Infinite Series
The infinite series that represents our repeating decimal can actually be summed up into a whole number. In mathematics, especially in the context of geometric series, infinite series can be calculated using specific formulas.
When we have a geometric series that repeats infinitely, we use the infinite geometric series sum formula:
\[S = \frac{a}{1-r}\]
Here, \(a\) stands for the first term of the series, and \(r\) is the common ratio. Applying this to our repeating decimal \(0.\overline{9}\):
\(S = \frac{0.9}{1 - 0.1} = \frac{0.9}{0.9} = 1\).
Thus, the sum of our series \(0.\overline{9}\) equals \(1\), showing that the repeating decimal \(0.\overline{9}\) actually equals the number \(1\).
When we have a geometric series that repeats infinitely, we use the infinite geometric series sum formula:
\[S = \frac{a}{1-r}\]
Here, \(a\) stands for the first term of the series, and \(r\) is the common ratio. Applying this to our repeating decimal \(0.\overline{9}\):
- First term \(a = 0.9\)
- Common ratio \(r = 0.1\)
\(S = \frac{0.9}{1 - 0.1} = \frac{0.9}{0.9} = 1\).
Thus, the sum of our series \(0.\overline{9}\) equals \(1\), showing that the repeating decimal \(0.\overline{9}\) actually equals the number \(1\).
Common Ratio
In a geometric series, the common ratio is crucial as it defines how each term progresses to the next. For \(0.\overline{9}\), the common ratio \(r = 0.1\). This means that each subsequent term in the series is 0.1 times the previous one.
To understand why the common ratio is so important:
The concept of a common ratio helps demystify how something infinite can result in a definitive value.
To understand why the common ratio is so important:
- It shows the regular pattern of multiplication that allows the series to consistently approach a particular value as the terms progress.
- The value of \(r\) determines how quickly the series converges to its sum; in our case, it converges to 1.
The concept of a common ratio helps demystify how something infinite can result in a definitive value.
Other exercises in this chapter
Problem 47
Use the Ratio Test to determine the convergence or divergence of the series. $$ \sum_{n=1}^{\infty} \frac{2^{n}}{n^{2}} $$
View solution Problem 47
Find the sum of the convergent series by using a well-known function. Identify the function and explain how you obtained the sum. $$ \sum_{n=1}^{\infty}(-1)^{n+
View solution Problem 48
Determine the convergence or divergence of the sequence with the given \(n\) th term. If the sequence converges, find its limit. \(a_{n}=n \sin \frac{1}{n}\)
View solution Problem 48
Write a power series that has the indicated interval of convergence. Explain your reasoning. (a) (-2,2) (b) (-1,1] (c) (-1,0) (d) [-2,6)
View solution