Problem 48
Question
(a) Graph the function \( f(x) = e^x + \ln | x - 4 | \) for \( 0 \le x \le 5 \). Do you think the graph is an accurate representation of \( f \)? (b) How would you get a graph that represents \( f \) better?
Step-by-Step Solution
Verified Answer
The graph needs adjustments near x = 4 and zooming techniques to represent the function accurately.
1Step 1: Understand the Function Components
The function consists of two parts: the exponential function \( e^x \) and the natural logarithm \( \ln |x - 4| \). Both of these functions have specific behaviors we need to consider. \( e^x \) increases rapidly for positive values of \( x \), while \( \ln |x - 4| \) has a vertical asymptote at \( x = 4 \). Our task is to evaluate this function within the interval \( 0 \le x \le 5 \).
2Step 2: Analyze Domain Restrictions
For the function \( f(x) = e^x + \ln | x - 4 | \), both \( e^x \) and \( \ln | x - 4 | \) must be defined. Specifically, \( |x - 4| \) cannot be zero, which implies \( x eq 4 \). Therefore, the function is undefined at \( x = 4 \) and has a discontinuity there.
3Step 3: Graph Function Components
Graph \( e^x \) independently to visualize its exponential growth. For \( \ln |x - 4| \), note the asymptote at \( x = 4 \), where the function approaches infinity as \( x \) approaches 4 from the right and negative infinity as \( x \) approaches 4 from the left. Plot these components on the same graph from \( x = 0 \) to \( x = 5 \).
4Step 4: Evaluate Combined Graph
Combine the graphs of \( e^x \) and \( \ln |x - 4| \). Notice the effect that the ln term has on the graph: there's a notable spike at \( x = 4 \). Evaluate how this impacts the overall graph shape and note inaccuracies around \( x = 4 \) due to the discontinuity.
5Step 5: Improve Graph Representation
To better represent \( f \), consider narrowing the range around the discontinuity at \( x = 4 \) to better visualize behavior on either side of the asymptote. Using a smaller range or zooming in on the region near the asymptote can improve clarity. Additionally, technology like graphing software can refine plots for better detail.
6Step 6: Conclusion
By better handling the range around the asymptote, using graphing tools, and understanding the discontinuity, the graph represents \( f(x) = e^x + \ln | x - 4 | \) more accurately. Recognize this adjustment enhances interpretation of behavior around \( x = 4 \).
Key Concepts
Exponential FunctionNatural LogarithmDiscontinuityAsymptote
Exponential Function
The exponential function is a fundamental mathematical function, denoted as \( e^x \). It is defined as the function where the constant \( e \) (approximately 2.718) is raised to the power of \( x \). This function has a few important characteristics:
- Rapid Growth: \( e^x \) increases quickly as \( x \) becomes larger. For positive values of \( x \), the exponential function grows exponentially. This means it gets bigger very fast as you move along the x-axis to the right.
- Positive Output: For all real numbers \( x \), the output of \( e^x \) is always positive.
- Non-Zero: Since \( e^x \) is positive, it never equals zero, which is vital when graphing or solving equations.
Natural Logarithm
The natural logarithm, represented as \( \ln(x) \), is the inverse operation of the exponential function \( e^x \). It is particularly interesting when applied to expressions like \( \ln |x - 4| \). Here are its key features:
- Inverse Relationship: The natural logarithm \( \ln(x) \) undoes the exponential growth of \( e^x \). It determines how many times you'd multiply \( e \) by itself to achieve \( x \).
- Undefined for Non-Positive Values: \( \ln(x) \) is not defined for \( x \leq 0 \). For our function, this means \( \ln |x - 4| \) creates a constraint where the expression inside the logarithm must be positive.
- Outputs Negative Values: For \( 0 < x < 1 \), logarithmic outputs are negative. This affects the graph significantly near the point of discontinuity.
Discontinuity
A discontinuity is a point on a graph where the function is not defined, leading to a "break" or "gap" in the plotting of the function. In the context of \( f(x) = e^x + \ln | x - 4 | \):
- Point of Discontinuity: The function is undefined at \( x = 4 \). At this point, the natural logarithm's requirement that \( x - 4 eq 0 \) directly causes the discontinuity.
- Impact on Graph: As \( x \) approaches 4, from either direction, the value of \( \ln |x - 4| \) escalates towards infinity or negative infinity, causing the graph to make sharp turns.
- Visualizing: To accurately visualize functions with discontinuities, focus on graphing smoothly on either side of these points. Utilize graphing software to better handle these abrupt changes in behavior.
Asymptote
An asymptote is a line that a graph approaches but never quite reaches. For the function \( f(x) = e^x + \ln |x - 4| \), there is a particularly poignant asymptote you must consider:
- Vertical Asymptote: This occurs at \( x = 4 \). The function \( \ln |x - 4| \) approaches infinity as \( x \) nears 4 from the right, and negative infinity from the left, implying a vertical asymptote.
- Graph Behavior: As \( x \) approaches the asymptote, the function’s value increases or decreases dramatically without actually reaching a finite value.
- Importance in Graphing: Recognizing where asymptotes lie helps accurately interpret and sketch the shape of a graph. Asymptotic behavior implies potential behavior not immediately obvious from equations.
Other exercises in this chapter
Problem 48
Let \( f(x) = 1/x \) and \( g(x) = 1/x^2 \). (a) Find \( (f \circ g)(x) \). (b) Is \( f \circ g \) continuous everywhere? Explain.
View solution Problem 48
Let \( g(x) = \text{sgn}(\sin x) \). (a) Find each of the following limits or explain why it does not exist. (i) \( \displaystyle \lim_{x \to 0^+}g(x) \) (ii) \
View solution Problem 49
Find the horizontal and vertical asymptotes of each curve. If you have a graphing device, check your work by graphing the curve and estimating the asymptotes. \
View solution Problem 49
Which of the following functions \( f \) has a removable discontinuity at \( a \)? If the discontinuity is removable, find a function \( g \) that agrees with \
View solution