Problem 48
Question
A breakfast cereal in advertised to contain \(110 \mathrm{mg}\) of sodium per \(100 \mathrm{~g}\) of the cereal. The per cent of sodium in the cereal is (a) \(0.110 \%\) (b) \(0.0110 \%\) (c) \(11.0 \%\) (d) \(0.22 \%\)
Step-by-Step Solution
Verified Answer
The correct answer is (a) 0.110%.
1Step 1: Identify the relationship
The problem states that there are \( 110 \, \text{mg} \) of sodium per \( 100 \, \text{g} \) of cereal. We need to convert this to a percentage by comparing it to the total mass of the cereal.
2Step 2: Convert units to grams
Since percentages are usually calculated based on the same unit, convert sodium from milligrams to grams: \( 110 \, \text{mg} = 0.110 \, \text{g} \).
3Step 3: Calculate the percentage
The percentage of sodium in the cereal is calculated using the formula \( \text{Percentage} = \left( \frac{\text{mass of sodium in g}}{\text{total mass of cereal in g}} \right) \times 100 \). Plugging in the numbers gives: \( \left( \frac{0.110}{100} \right) \times 100 = 0.11 \% \).
4Step 4: Choose the correct answer
Compare the calculated percentage to the given options: (a) \( 0.110 \% \), (b) \( 0.0110 \% \), (c) \( 11.0 \% \), (d) \( 0.22 \% \). The correct answer is (a) \( 0.110 \% \).
Key Concepts
Unit ConversionMass PercentageComparison of Values
Unit Conversion
Unit conversion is an essential skill in science and mathematics that helps in comparing different measurements easily. Here, you'll learn how to convert units effectively, which ensures accuracy in calculations and problem-solving.
In the original exercise, the sodium content is initially given in milligrams, while the cereal's mass is in grams. For comparing these values, we need them to share the same measurement unit. That is why the sodium is converted from milligrams to grams.
In the original exercise, the sodium content is initially given in milligrams, while the cereal's mass is in grams. For comparing these values, we need them to share the same measurement unit. That is why the sodium is converted from milligrams to grams.
- There are 1000 milligrams (mg) in 1 gram (g).
- To convert milligrams to grams, divide by 1000. So, 110 mg becomes 0.110 g.
Mass Percentage
Mass percentage gives you a way to express the concentration of a component in a mixture as a part of the whole. It tells you how much of an ingredient is present in a certain amount of material.
To calculate the mass percentage, you can utilize the formula:
To calculate the mass percentage, you can utilize the formula:
- \[\text{Percentage} = \left( \frac{\text{mass of component in g}}{\text{total mass in g}} \right) \times 100 \]
- Using the cereal problem as an example: \[\text{Percentage of sodium} = \left( \frac{0.110 \text{ g of sodium}}{100 \text{ g of cereal}} \right) \times 100 = 0.110 \% \]
Comparison of Values
In the scenario of the cereal's sodium content, several options are given for the percentage value. Comparing calculated values to given ones is critical for correctly interpreting and assessing data.
When you analyze the problem and calculate the percentage using the conversion and formula methods discussed, your result should match one of the given options. This comparison allows you to verify your answer and ensure its accuracy.
When you analyze the problem and calculate the percentage using the conversion and formula methods discussed, your result should match one of the given options. This comparison allows you to verify your answer and ensure its accuracy.
- The calculated sodium percentage is \(0.110\%\).
- Let’s compare it to the provided options:
- Option (a) \(0.110\%\), which matches our calculation.
- Other options: (b) \(0.0110\%\), (c) \(11.0\%\), (d) \(0.22\%\) do not match.
Other exercises in this chapter
Problem 44
Which of the following statement is correct? (a) 1 mole of electrons weighs \(5.4 \mathrm{mg}\) (b) 1 mole of electrons weighs \(5.4 \mathrm{~kg}\) (c) 1 mole o
View solution Problem 47
Which of the following is the odd one with regard to mass? (a) \(1 \mathrm{~g}\) atom of sulphur (b) \(0.5\) moles of \(\mathrm{CO}_{2}\) (c) 1 mole of \(\mathr
View solution Problem 50
The number of significant figures in \(306.45\) and 40440 are respectively (a) 4,5 (b) 5,5 (c) 5,4 (d) 4,6
View solution Problem 51
The quantity of \(\frac{\mathrm{PV}}{\mathrm{K}_{\mathrm{B}} \mathrm{T}}\) represents the (a) molar mass of a gas (b) number of molecules in a gas (c) mass of g
View solution