Problem 48
Question
A 55-kg gymnast hangs vertically from a pair of parallel rings. (a) If the ropes supporting the rings are attached to the ceiling directly above, what is the tension in each rope? (b) If the ropes are supported so that they make an angle of \(45^{\circ}\) with the ceiling, what is the tension in each rope?
Step-by-Step Solution
Verified Answer
(a) 269.5 N (b) 381.03 N in each rope.
1Step 1: Understanding the Forces
The gymnast's weight is distributed equally between the two ropes. Therefore, each rope supports half of the gymnast's weight.
2Step 2: Calculate Weight of Gymnast
Calculate the weight of the gymnast using the formula for weight: \[ W = mg \]where \( m = 55 \text{ kg} \) and \( g = 9.8 \text{ m/s}^2 \). Thus, \( W = 55 \times 9.8 = 539 \text{ N} \).
3Step 3: Calculate Tension When Ropes are Vertical
Since the ropes are vertical, the weight is equally distributed between the two ropes. Therefore, the tension in each rope is:\[ T_1 = T_2 = \frac{W}{2} = \frac{539}{2} = 269.5 \text{ N}. \]
4Step 4: Analyze Forces with Angled Ropes
When the ropes make a \(45^{\circ}\) angle with the ceiling, each tension \(T\) is a component of the vertical force equal to half the weight of the gymnast.
5Step 5: Use Trigonometry for Angled Ropes
The vertical component of the tension in each rope is \( T \times \cos(45^\circ) \). This must equal half the weight:\[ T \cdot \cos(45^\circ) = \frac{539}{2} \].
6Step 6: Calculate Tension in Each Rope at Angle
Solving for \(T\), we get:\[ T = \frac{539/2}{\cos(45^\circ)} = \frac{269.5}{0.7071} \approx 381.03 \text{ N}. \]
Key Concepts
Tension in RopesTrigonometry in PhysicsForces in Equilibrium
Tension in Ropes
Tension in ropes is a fundamental concept in physics, especially when studying equilibrium problems. When a gymnast hangs from ropes, the tension is the force exerted by the ropes that supports the weight of the gymnast. This happens because the ropes are pulling upwards against gravity, preventing the gymnast from falling.
- The tension will always adjust to be equal to the forces necessary to keep the system (like the gymnast) in equilibrium.
- When the ropes are vertical, the entire gravitational force or weight is shared equally between the ropes. This means that if there are two ropes, each rope carries half of the load.
- When the ropes are angled, the situation becomes a bit more complex, but tension still serves the same purpose—holding the gymnast in place.
Trigonometry in Physics
Trigonometry is a key mathematical tool used in physics to resolve forces acting at angles. In our gymnast example, when the ropes are angled, trigonometry comes into play to determine the tension in the ropes.
Using trigonometry allows us to break down forces into components:
Using trigonometry allows us to break down forces into components:
- The vertical component, which opposes gravity.
- The horizontal component, which is often balanced by an equal and opposite force.
- The formula \(T \cdot \cos(45^{\circ}) = \frac{539}{2}\) is derived from setting the vertical component of tension equal to the gymnast’s weight supported by each rope.
- Knowing \(\cos(45^{\circ}) = 0.7071\), the required tension \(T\) is solved by rearranging the equation to \(T = \frac{269.5}{0.7071}\).
Forces in Equilibrium
Forces in equilibrium are essential when evaluating how objects, like our gymnast, remain stationary despite multiple forces acting on them. When discussing forces in equilibrium:
- A system is said to be in equilibrium if the sum of all forces and the sum of all moments (torques) acting on it are zero.
- The gymnast hanging at rest implies that all forces are balancing out.
- The ropes' tension fully supports the gymnast’s weight, providing a net force of zero.
- Vertically, the downward gravitational force is balanced by the upward component of the tension in the ropes.
- Horizontally, if any, forces are balanced such that there is no lateral movement.
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