Problem 48
Question
\(43-50\) . Solve the equation graphically in the given interval. State each answer rounded to two decimals. $$ 1+\sqrt{x}=\sqrt{1+x^{2}} ;[-1,5] $$
Step-by-Step Solution
Verified Answer
The graphs intersect around x = 0.68, indicating the solution.
1Step 1: Identify Functions
Identify the functions represented in the equation: The left side of the equation is represented by the function \( f(x) = 1 + \sqrt{x} \). The right side of the equation is represented by the function \( g(x) = \sqrt{1 + x^2} \).
2Step 2: Graph the Functions
Plot the functions \( f(x) \) and \( g(x) \) on a graph for the interval \([-1, 5]\). Use graphing software or a graphing calculator to visualize these two functions.
3Step 3: Find the Intersection Points
Observe where the two graphs intersect within the interval \([-1, 5]\). The intersection points represent the values of \( x \) where the equation \( 1 + \sqrt{x} = \sqrt{1 + x^2} \) holds true.
4Step 4: Approximate and Round the Intersection Points
From the graph, approximate the \( x \)-coordinates where the two graphs intersect. Ensure to round these values to two decimal places to obtain the solutions within the specified precision.
Key Concepts
Graphing FunctionsIntersection PointsApproximationRounding Numbers
Graphing Functions
Graphing functions is a visual way to understand mathematical relationships. Each function is like a special equation that describes a unique set of points on a graph. In our problem, we have two functions to consider:
- The first function, \( f(x) = 1 + \sqrt{x} \), rises slowly as \( x \) increases because it is a square root function combined with a constant.
- The second function, \( g(x) = \sqrt{1 + x^2} \), grows quicker as \( x \) increases due to the square root of a squared term plus one.
Intersection Points
Intersection points are where two graph lines (functions) cross each other. These points are important because they represent the solutions to an equation where the two functions are equal. In our example:
- To find the intersection, look at the graph and see where the curve of \( f(x) = 1 + \sqrt{x} \) meets the curve of \( g(x) = \sqrt{1 + x^2} \).
- It's within these intersection points that the values of \( x \) make both sides of our original equation true, thus solving the equation graphically.
Approximation
Approximation is necessary when calculating exact values directly from the graph is difficult. Graphs provide a visual representation and help us see where functions intersect, but they don't always give precise values for those \( x \)-coordinates. This is where approximation comes in. With a graph:
- You estimate the \( x \)-values where the functions intersect by observing closely.
- In many cases, like our problem, you might need to adjust your estimates to be as close as possible to the true intersection points.
Rounding Numbers
Rounding numbers involves adjusting a number to a specified degree of precision, often to make calculations simpler. When you round, you're making the number easier to use at the cost of some precision.
- In our exercise, solutions are to be rounded to two decimal places.
- This is often the standard in scientific work where approximated values need to be concise yet accurate enough for practical use.
- If it's 5 or more, increase the second decimal by one.
- If it's less than 5, leave the second decimal place as is.
Other exercises in this chapter
Problem 47
Show that the points \(A(-2,9), B(4,6), C(1,0),\) and \(D(-5,3)\) are the vertices of a square.
View solution Problem 48
Find the slope and y-intercept of the line, and draw its graph. $$ 2 x-5 y=0 $$
View solution Problem 48
\(41-48\) Find the \(x\) - and \(y\) -intercepts of the graph of the equation. $$ x^{2}-x y+y=1 $$
View solution Problem 48
Show that the points \(A(-1,3), B(3,11),\) and \(C(5,15)\) are collinear by showing that \(d(A, B)+d(B, C)=d(A, C)\).
View solution