Problem 47
Question
Write the quotient in standard form. $$\frac{5}{4-2 i}$$
Step-by-Step Solution
Verified Answer
The quotient in standard form is \(\frac{5}{3} + \frac{5i}{6}\)
1Step 1: Identification of Conjugate
Firstly, identify the conjugate of the denominator. The conjugate of a complex number \(a + bi\) is \(a - bi\). So, the conjugate of \(4 - 2i\) is \(4 + 2i\).
2Step 2: Multiplication with Conjugate
Next, multiply the numerator and the denominator by this conjugate such that: \[ \frac{5}{4-2 i} \times \frac{4+2i}{4+2i} \]
3Step 3: Distributive Property
Now apply the distributive property separately in the numerator and the denominator. The numerator would be \(20 + 10i\) and the denominator would be \(16 + 8i - 8i -4\) after simplifying.
4Step 4: Simplification
Simplify the expressions to get the (a+bi) form. The numerator remains the same, but the denominator simplifies to \(16 - 4 = 12\), so the final expression becomes \( \frac{20 + 10i}{12}\).
5Step 5: Divide out common factor
Finally, you divide out the common factor to get the expression in lowest terms. The common factor is 2. So, you divide each part of the numerator and the denominator by 2: \( \frac{10 + 5i}{6}\) or \(\frac{5}{3} + \frac{5i}{6}\).
Other exercises in this chapter
Problem 47
Sketch the graph of the rational function. To aid in sketching the graphs, check for intercepts, symmetry, vertical asymptotes, and horizontal asymptotes. $$f(x
View solution Problem 47
Write the polynomial (a) as the product of factors that are irreducible over the rationals, (b) as the product of linear and quadratic factors that are irreduci
View solution Problem 47
Match the cubic function with the numbers of rational and irrational zeros. (a) Rational zeros: \(0 ; \quad\) Irrational zeros: 1 (b) Rational zeros: \(3 ; \qua
View solution Problem 47
Use synthetic division to find each function value. \(f(x)=2 x^{3}-3 x^{2}+8 x-14\) (a) \(f(2)\) (b) \(f(-1)\) (c) \(f(1.1)\) (d) \(f(3)\)
View solution