Problem 47
Question
Write each of the following in terms of \(i\), perform the indicated operations, and simplify. $$ \sqrt{-9} \sqrt{-6} $$
Step-by-Step Solution
Verified Answer
The expression simplifies to \(-3\sqrt{6}\).
1Step 1: Express each square root in terms of 'i'
The expression involves the square roots of negative numbers, which can be expressed in terms of the imaginary unit 'i'. Recall that the square root of a negative number \(-a\) is \( ext{i} imes ext{sqrt}(a)\).Thus,\(\sqrt{-9} = \sqrt{9} \times i = 3i\) and \(\sqrt{-6} = \sqrt{6} \times i = \sqrt{6}i\).
2Step 2: Multiply the expressions
Now that both expressions are in terms of 'i', we perform the multiplication:\(\sqrt{-9} \times \sqrt{-6} = (3i) \times (\sqrt{6}i)\).
3Step 3: Simplify the expression
Multiply the coefficients and simplify:- Multiply the real numbers: \(3 \times \sqrt{6} = 3\sqrt{6}\)- Multiply the imaginary parts: \(i \times i = i^2 = -1\)Therefore, the expression simplifies to:\((3\sqrt{6})(-1) = -3\sqrt{6}\).
Key Concepts
Square RootsSimplifying ExpressionsMultiplication of Complex Numbers
Square Roots
Square roots are operations that find the number which, when multiplied by itself, yields the original number. However, finding the square root of negative numbers requires special treatment. This is where the concept of imaginary numbers comes in. An imaginary number is a number that can be written as a real number multiplied by the imaginary unit 'i', where the key characteristic of 'i' is that it satisfies the equation \(i^2 = -1\).
When dealing with the square roots of negative numbers, as in our exercise, the expression can be rewritten in terms of 'i'. For example, the square root of a negative number \(-a\) can be expressed as \(\sqrt{-a} = i \cdot \sqrt{a}\). This allows us to handle operations involving square roots of negative numbers more easily.
Understanding this principle is crucial for solving complex number problems correctly, as it transforms seemingly unsolvable expressions into manageable forms.
When dealing with the square roots of negative numbers, as in our exercise, the expression can be rewritten in terms of 'i'. For example, the square root of a negative number \(-a\) can be expressed as \(\sqrt{-a} = i \cdot \sqrt{a}\). This allows us to handle operations involving square roots of negative numbers more easily.
Understanding this principle is crucial for solving complex number problems correctly, as it transforms seemingly unsolvable expressions into manageable forms.
Simplifying Expressions
Simplifying expressions, especially when dealing with imaginary numbers, involves breaking down and reducing the expression to its simplest form. The prime goal is to eliminate as much complexity as possible without changing the expression’s overall value.
In our example, after rewriting square roots using 'i', we need to simplify further by multiplying these expressions. Simplification can follow a few key steps:
Remember, the better you simplify, the easier it is to work with the expression later on.
In our example, after rewriting square roots using 'i', we need to simplify further by multiplying these expressions. Simplification can follow a few key steps:
- Express each part of the expression clearly in terms of real numbers and 'i'.
- Perform arithmetic operations such as multiplication or distribution normally but keep track of the imaginary unit rules (\(i^2 = -1\)).
- Combine like terms wherever feasible to reach a simpler form.
Remember, the better you simplify, the easier it is to work with the expression later on.
Multiplication of Complex Numbers
When multiplying complex numbers, especially those involving the imaginary unit 'i', it is important to apply the distributive property and rules for operations correctly. In our problem, we have two parts \( (3i) \) and \( (\sqrt{6}i) \) that need to be multiplied.
This multiplication involves:
Understanding the multiplication of complex numbers is vital, as it helps streamline the process and ensure accuracy in arithmetic with imaginary numbers.
This multiplication involves:
- Multiplying real coefficients together, which gives us \(3 \times \sqrt{6} = 3\sqrt{6}\),
- Multiplying the imaginary units (i \times i) together, which leads to \(i^2\) that equals \(-1\).
Understanding the multiplication of complex numbers is vital, as it helps streamline the process and ensure accuracy in arithmetic with imaginary numbers.
Other exercises in this chapter
Problem 47
Set up an equation and solve each problem. Suppose that the sum of two whole numbers is 9 , and the sum of their reciprocals is \(\frac{1}{2}\). Find the number
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Solve each quadratic equation using the method that seems most appropriate. $$ (x-3)^{2}=12 $$
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Set up an equation and solve each problem. The difference between two whole numbers is 8 , and the difference between their reciprocals is \(\frac{1}{6}\). Find
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Solve each quadratic equation using the method that seems most appropriate. $$ x^{2}=16 x $$
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