Problem 47
Question
Write each complex number in the trigonometric form \(r(\cos \theta+i \sin \theta),\) where \(r\) is exact and \(0^{\circ} \leq \theta<360^{\circ}\) $$1+i \sqrt{3}$$
Step-by-Step Solution
Verified Answer
The trigonometric form is \( 2(\cos 60^{\circ} + i \sin 60^{\circ}) \).
1Step 1: Find the Magnitude
For a complex number in the form \( a + bi \), the magnitude \( r \) is calculated using the formula \( r = \sqrt{a^2 + b^2} \). Here, \( a = 1 \) and \( b = \sqrt{3} \). Substitute these values: \( r = \sqrt{1^2 + (\sqrt{3})^2} = \sqrt{1 + 3} = \sqrt{4} = 2 \).
2Step 2: Determine the Angle
The angle \( \theta \) can be found using the formula \( \tan \theta = \frac{b}{a} \). So, \( \tan \theta = \frac{\sqrt{3}}{1} = \sqrt{3} \). The angle for which \( \tan \theta = \sqrt{3} \) is \( \theta = 60^{\circ} \).
3Step 3: Write the Trigonometric Form
Now that we have \( r = 2 \) and \( \theta = 60^{\circ} \), the complex number \( 1 + i \sqrt{3} \) in trigonometric form is \( 2(\cos 60^{\circ} + i \sin 60^{\circ}) \).
Key Concepts
Complex NumbersMagnitude of Complex NumbersAngle of Complex NumbersPolar Coordinates
Complex Numbers
Complex numbers are a significant part of mathematics, where they extend the idea of one-dimensional number lines into two dimensions. They are of the form \(a + bi\), where \(a\) and \(b\) are real numbers, and \(i\) is the imaginary unit, defined by the equation \(i^2 = -1\).
- Real Part: This is the "\(a\)" in \(a + bi\), representing the horizontal axis on a complex plane.
- Imaginary Part: The "\(b\)" value, which pairs with the imaginary unit "\(i\)", showing the vertical positioning.
Magnitude of Complex Numbers
The magnitude, often referred to as the modulus, of a complex number intuitively represents its distance from the origin (0,0) on the complex plane. For a complex number \(a + bi\), we calculate its magnitude \(r\) using the formula \[ r = \sqrt{a^2 + b^2}\]This formula derives from the Pythagorean theorem, recognizing that every complex number maps onto a right triangle's hypotenuse.
For example, if your complex number is \(1 + i \sqrt{3}\), then the calculations would unfold as follows:
For example, if your complex number is \(1 + i \sqrt{3}\), then the calculations would unfold as follows:
- Identify: \(a = 1\), \(b = \sqrt{3}\)
- Substitute: \(r = \sqrt{1^2 + (\sqrt{3})^2} = \sqrt{1 + 3} = \sqrt{4} = 2\)
Angle of Complex Numbers
To fully express a complex number in its trigonometric form, we require not just its magnitude but also an angle that encapsulates its direction relative to the positive real axis. This angle, known as \(\theta\), can be determined by the formula \[ \tan \theta = \frac{b}{a}\]Using this relationship, if we have a complex number \(1+i\sqrt{3}\), we calculate:
- Identify: \(a = 1\), \(b = \sqrt{3}\)
- Calculate: \(\tan \theta = \frac{\sqrt{3}}{1} = \sqrt{3}\)
- Recognize: An angle \(\theta\) satisfying \(\tan \theta = \sqrt{3}\) is \(60^{\circ}\).
Polar Coordinates
Polar coordinates offer a new lens through which to view complex numbers, transitioning from Cartesian's \((x, y)\) coordinates to a system denoted by a radius and angle \((r, \theta)\). This form aligns with vectors, making it useful in fields like physics and engineering for representing rotational dynamics.
In polar form, a complex number's components are depicted as:
In polar form, a complex number's components are depicted as:
- Magnitude (\(r\)): The length from the origin, or "how far."
- Angle (\(\theta\)): The direction or "which way," oriented counter-clockwise from the positive x-axis.
Other exercises in this chapter
Problem 47
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