Problem 47
Question
Write an equation of the line that passes through the points. (-3,1),(4,-2)
Step-by-Step Solution
Verified Answer
So, the equation of the line passing through the given points is \(y = \frac{-3}{7}x + \frac{-2}{7}\)
1Step 1: Calculate the Slope
To find the slope (m) of a line passing through two points \((-3,1)\) and \((4,-2)\), we use the formula \[m = \frac{y_2 - y_1}{x_2 - x_1}\], where \((x_1, y_1)\) and \((x_2, y_2)\) are the coordinates of the two points. So, \(m = \frac{-2 - 1}{4 - (-3)} = \frac{-3}{7}\).
2Step 2: Use the Point-Slope Form
Once we've found the slope, we can use the point-slope form of a line to find the equation. The point-slope form is written as: \[y - y_1 = m(x - x_1)\]. Using one of the given points, for example \((-3,1)\), and the slope calculated in the previous step, we get: \[y - 1 = \frac{-3}{7}(x - (-3))\].
3Step 3: Simplify Equation
Finally, simplify the equation to put it in the slope-intercept form (\(y = mx + b\)): \[y = \frac{-3}{7}x - \frac{9}{7} + 1 = \frac{-3}{7}x + \frac{-2}{7}\].
Key Concepts
Slope CalculationPoint-Slope FormSlope-Intercept Form
Slope Calculation
Calculating the slope of a line involves determining its steepness or incline. This is done using the coordinates of two points that the line passes through. If you have two points, labeled as
For example, to find the slope of a line that passes through
\[ m = \frac{-2 - 1}{4 - (-3)} = \frac{-3}{7}\]
So, the slope of this line is \(-\frac{3}{7}\), indicating a gently descending line.
- \((x_1, y_1)\) and
- \((x_2, y_2)\),
For example, to find the slope of a line that passes through
- \((-3, 1)\) and
- \((4, -2)\),
\[ m = \frac{-2 - 1}{4 - (-3)} = \frac{-3}{7}\]
So, the slope of this line is \(-\frac{3}{7}\), indicating a gently descending line.
Point-Slope Form
Point-slope form is a useful way of expressing the equation of a line when you know both the slope and a single point on the line. The formula is:
Using point-slope form, you can easily derive an equation that represents your line. In our exercise, we've calculated the slope to be \(-\frac{3}{7}\), and we can use one of our given points, say \((-3,1)\).
Substitute these values into the formula:\[y - 1 = \frac{-3}{7}(x - (-3))\]
This undoubtedly yields an accurate starting equation for our line, which can be simplified further to express in other forms.
- \(y - y_1 = m(x - x_1)\)
- \(m\) is the slope of the line, and
- \((x_1, y_1)\) is the specific point the line passes through.
Using point-slope form, you can easily derive an equation that represents your line. In our exercise, we've calculated the slope to be \(-\frac{3}{7}\), and we can use one of our given points, say \((-3,1)\).
Substitute these values into the formula:\[y - 1 = \frac{-3}{7}(x - (-3))\]
This undoubtedly yields an accurate starting equation for our line, which can be simplified further to express in other forms.
Slope-Intercept Form
The slope-intercept form is widely recognized for its practicality and straightforwardness. It expresses a linear equation as:
In our solution, after using the point-slope form, we simplified it to slope-intercept form. Beginning with:\[y - 1 = \frac{-3}{7}(x + 3)\]
Which simplifies to:\[y = \frac{-3}{7}x - \frac{9}{7} + 1\]Continuing:\[y = \frac{-3}{7}x + \frac{-2}{7}\]
Here, the equation \(y = \frac{-3}{7}x + \frac{-2}{7}\) efficiently describes the line's slope as \(-\frac{3}{7}\) and y-intercept as \(\frac{-2}{7}\), providing a complete and user-friendly representation of the linear relationship.
- \(y = mx + b\)
- \(m\) represents the slope, and
- \(b\) is the y-intercept, the point where the line crosses the y-axis (when \(x = 0\)).
In our solution, after using the point-slope form, we simplified it to slope-intercept form. Beginning with:\[y - 1 = \frac{-3}{7}(x + 3)\]
Which simplifies to:\[y = \frac{-3}{7}x - \frac{9}{7} + 1\]Continuing:\[y = \frac{-3}{7}x + \frac{-2}{7}\]
Here, the equation \(y = \frac{-3}{7}x + \frac{-2}{7}\) efficiently describes the line's slope as \(-\frac{3}{7}\) and y-intercept as \(\frac{-2}{7}\), providing a complete and user-friendly representation of the linear relationship.
Other exercises in this chapter
Problem 46
Write an equation of a line through \((0,2)\) that is perpendicular to \(y=-4 x+6\)
View solution Problem 46
Use the following information. You are moving to Houston, Texas, and are switching your cellular phone company. Your new peak air time rate in Houston is \(\$ .
View solution Problem 47
Write an equation in standard form of the line that passes through the two points. $$(-4,1),(2,-5)$$
View solution Problem 47
Write an equation of the line in slope-intercept form. The slope is \(-2 ;\) the \(y\) -intercept is \(-6\)
View solution