Problem 47
Question
Write an equation for a parabola with vertex at \((-3,-4)\) and \(y\) -intercept 8
Step-by-Step Solution
Verified Answer
The equation of the parabola is \(y = \frac{4}{3}(x + 3)^2 - 4\).
1Step 1: Understand the Parabola Equation
A parabola with a vertical axis of symmetry can be described by the equation \( y = a(x - h)^2 + k \), where \((h, k)\) is the vertex of the parabola.
2Step 2: Substitute the Vertex into the Equation
Given that the vertex of the parabola is \((-3, -4)\), we substitute \(h = -3\) and \(k = -4\) into the equation: \[ y = a(x + 3)^2 - 4 \]
3Step 3: Use the Y-Intercept to Find the Coefficient a
The \(y\)-intercept is the value of \(y\) when \(x = 0\). Since the \(y\)-intercept is \(8\), substitute \(x = 0\) and \(y = 8\) into the equation: \[ 8 = a(0 + 3)^2 - 4 \] The equation simplifies to: \[ 8 = 9a - 4 \]
4Step 4: Solve for a
To find \(a\), solve the equation from Step 3: 1. Add 4 to both sides: \[ 12 = 9a \] 2. Divide both sides by 9: \[ a = \frac{12}{9} = \frac{4}{3} \]
5Step 5: Write the Equation
Substitute the value of \(a\) back into the parabola's equation: \[ y = \frac{4}{3}(x + 3)^2 - 4 \] This is the equation of the parabola with the specified vertex and \(y\)-intercept.
Key Concepts
Vertex FormSolving for aParabola FeaturesY-Intercept in Parabolas
Vertex Form
The vertex form of the equation of a parabola is an essential tool when studying quadratic functions. This form can be written as \( y = a(x - h)^2 + k \), where \((h, k)\) represents the vertex of the parabola.
The vertex is simply the highest or lowest point on the graph, depending on whether the parabola opens upwards or downwards. In this equation:
The vertex is simply the highest or lowest point on the graph, depending on whether the parabola opens upwards or downwards. In this equation:
- \(a\) determines the direction and width of the parabola.
- \(h\) and \(k\) indicate the coordinates of the vertex.
Solving for a
In the context of a parabola, the coefficient \(a\) in the vertex form equation \(y = a(x - h)^2 + k\) plays a vital role in defining the parabola's shape. When constructing a specific parabola, as in the given exercise, finding the value of \(a\) is crucial.
To solve for \(a\), you need another point on the parabola in addition to the vertex. Often, the y-intercept is used for this purpose because it's straightforward to find. Here's a quick way to solve for \(a\):
To solve for \(a\), you need another point on the parabola in addition to the vertex. Often, the y-intercept is used for this purpose because it's straightforward to find. Here's a quick way to solve for \(a\):
- Identify the known points, such as the vertex and y-intercept.
- Substitute these values into the vertex form equation to create an equation.
- Solve this equation for \(a\).
Parabola Features
Parabolas have key features that define their shape and position on a graph. Understanding these features helps in graphing and analyzing quadratic functions, like the one in our exercise.
Here are the essential features to consider:
Here are the essential features to consider:
- Vertex: The turning point of the parabola, where it reaches its maximum or minimum.
- Axis of Symmetry: A vertical line through the vertex, splitting the parabola into two mirror-image halves.
- Direction: Determined by \(a\), the parabola can open upwards (if \(a > 0\)) or downwards (if \(a < 0\)).
- Width: The value of \(a\) also affects the width; smaller \(|a|\) values result in a wider parabola, while larger \(|a|\) values produce a narrower one.
Y-Intercept in Parabolas
The y-intercept of a parabola is where it crosses the y-axis, giving a point with coordinates \((0, y)\). It's an essential point because it offers a real value to work with when deriving the equation of the parabola from its vertex form.
To find the y-intercept in a parabola equation:
To find the y-intercept in a parabola equation:
- Set \(x = 0\) in the equation \(y = a(x - h)^2 + k\).
- Simplify to find \(y\).
Other exercises in this chapter
Problem 47
The supporting cables of the Golden Gate Bridge approximate the shape of a parabola. The parabola can be modeled by \(y=0.00012 x^{2}+6,\) where \(x\) represent
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