Problem 47
Question
WorkPatch \(10.2\) had you assign oxidation states to the oxygen atoms in ozone. The answer was \(-1\) and 0 for the terminal (end) oxygen atoms and \(+1\) for the central oxygen atom. But now, a student claims the oxidation states are \(+1\) for the central oxygen atom and \(-1 / 2\) for the terminal oxygen atoms. He is also right. Explain why.
Step-by-Step Solution
Verified Answer
Both the given answer and the student's claim are valid because assigning oxidation states is an arbitrary process used to help describe molecule behavior. In ozone, resonance structures play a significant role in the distribution of electrons, allowing for alternative oxidation state representations as long as the molecule's total charge remains consistent. These numbers are not absolute values but a method for describing electron distribution in a molecule.
1Step 1: Understand the structure of ozone.
Ozone (O3) is a molecule composed of three oxygen atoms arranged in a bent structure with an angle of approximately 116.8 degrees. The central oxygen atom is connected to two terminal oxygen atoms through a single bond and a double bond. The molecule's resonance structures allow the electrons to be distributed evenly among the three oxygen atoms. Thus, it is essential to consider these resonance structures when assigning oxidation states.
2Step 2: Assign oxidation states using the given answer (by WorkPatch 10.2).
Using the answer provided (-1 and 0 for the terminal oxygen atoms and +1 for the central oxygen atom), we consider the following oxidation states for the ozone molecule:
1. For the terminal oxygen atom with a single bond: -1
2. For the terminal oxygen atom with a double bond (two bonds): 0
3. For the central oxygen atom: +1
This distribution of oxidation states fulfills the requirement that the sum of the oxidation states should equal the total charge of the molecule (0 in this case), since (-1) + (0) + (+1) = 0.
3Step 3: Assign oxidation states using the student's claim.
According to the student's claim, the oxidation states are +1 for the central oxygen atom and -1/2 for the terminal oxygen atoms. We consider the following oxidation state distribution:
1. For both terminal oxygen atoms: -1/2 each
2. For the central oxygen atom: +1
This distribution also fulfills the requirement that the sum of oxidation states equals the total charge of the molecule since (+1) + (-1/2) + (-1/2) = 0.
4Step 4: Explain why both answers are valid.
Both the given answer and the student's claim are valid because assigning oxidation states is an arbitrary process used to help describe molecule behavior. In this case, the resonance structures of ozone play a significant role in the distribution of electrons. The oxidation states provided by the student are an alternative representation that is also valid because the molecule's total charge remains consistent with both oxidation state assignments. It is essential to understand that these numbers are not absolute values but a method for describing electron distribution in a molecule.
Key Concepts
Resonance StructuresOzone MoleculeElectron DistributionMolecular Charge Balancing
Resonance Structures
In chemistry, resonance structures refer to different ways of depicting the same molecule, particularly in representing delocalized electrons.
For molecules like ozone, this is an essential concept because it describes how electrons can be arranged in multiple configurations while still representing the same molecular structure.
This delocalization affects the oxidation states and represents one of the reasons why alternate oxidation numbers might still make sense. They reflect how electrons are shared, not strictly owned by specific atoms.
For molecules like ozone, this is an essential concept because it describes how electrons can be arranged in multiple configurations while still representing the same molecular structure.
- Resonance structures are not distinct molecules; they are alternate representations that help us understand the electron distribution.
- They emphasize the idea that electrons can be shared differently among atoms, creating a more versatile framework than static single and double bonds alone can depict.
This delocalization affects the oxidation states and represents one of the reasons why alternate oxidation numbers might still make sense. They reflect how electrons are shared, not strictly owned by specific atoms.
Ozone Molecule
Ozone is an important molecule ( ext{O}_3) notable for its role in the Earth's atmosphere, particularly for absorbing the ultraviolet radiation from the sun. Structurally, it consists of three oxygen atoms arranged in a bent conformation with an angle around 116.8 degrees, leading to specific bonding interactions.
The ability of ozone to depict multiple states speaks to the flexibility and complexity inherent in chemical bonding, revealing reasons why different interpretations of oxidation states might be equally correct.
- The central oxygen atom is linked by one double bond and one single bond to the terminal oxygen atoms.
- This asymmetric bond character is what permits resonance, allowing electron density to oscillate between various forms.
The ability of ozone to depict multiple states speaks to the flexibility and complexity inherent in chemical bonding, revealing reasons why different interpretations of oxidation states might be equally correct.
Electron Distribution
The concept of electron distribution involves understanding how electrons are shared within a molecule. In resonance structures, the electrons are not confined to one bond or atom but are distributed across a molecule, providing stability and energy balance.
- In ozone, the resonance structures imply that electrons can move freely along the bonds, not being permanently fixed to any single oxygen atom.
- This means the electron distribution is dynamic, causing varied states of electron sharing at any given time.
Molecular Charge Balancing
Molecular charge balancing refers to the principle that the sum of oxidation states in a neutral molecule must equal its total charge, which is zero for neutral molecules like ozone. This principle is foundational in chemical analysis for maintaining consistency in understanding molecular behavior.
In ozone, the total charge naturally balances through its resonance and electron distribution.
In ozone, the total charge naturally balances through its resonance and electron distribution.
- When considering the oxidation states (-1, 0, +1) for the terminal and central atoms, the math (-1) + (0) + (+1) = 0 ensures that the molecule remains neutral.
- Similarly, the (-1/2, +1, -1/2) configuration does the same as (+1) + (-1/2) + (-1/2) = 0.
Other exercises in this chapter
Problem 45
Use the shortcut rules to assign an oxidation state to each atom in: (a) \(\mathrm{O}^{2-}\) (b) \(\mathrm{Li}_{3} \mathrm{~N}\) (c) \(\mathrm{MgSO}_{4}\) (d) \
View solution Problem 46
Consider \(\mathrm{ClO}^{-}\) and \(\mathrm{AlCl}_{3}\). For one of these substances, the halide shortcut rule works. For the other, it does not. (a) Which one
View solution Problem 49
What do the terms oxidation and reduction mean with regard to valence electrons?
View solution Problem 50
When is an oxidizing agent also the species that gets oxidized? Explain.
View solution