Problem 47
Question
When expressed as a decimal, is \(\frac{7}{9}\) a terminating or repeating decimal?
Step-by-Step Solution
Verified Answer
\( \frac{7}{9} \) is a repeating decimal with the digit 7 repeating.
1Step 1: Understanding Decimals
To determine if a fraction like \( \frac{7}{9} \) is a terminating or repeating decimal, we first need to understand the decimal representations. A terminating decimal has a finite number of digits after the decimal point, while a repeating decimal has one or more repeating digits after the decimal point.
2Step 2: Calculate the Decimal
Convert \( \frac{7}{9} \) to a decimal by performing long division of 7 divided by 9. Start dividing 7 by 9, which gives 0. The remainder becomes 70 when you bring down 0 to the tenths place. Divide 70 by 9, which equals 7 with a remainder of again 7, forming a repeating sequence.
3Step 3: Identifying the Pattern
Observe the outcome of the division. After performing the division, you notice that the decimal part is 0.777... The digit 7 repeats indefinitely.
4Step 4: Classifying the Decimal
Since the decimal form of \( \frac{7}{9} \) is 0.777..., and the digit 7 repeats indefinitely, \( \frac{7}{9} \) is classified as a repeating decimal.
Key Concepts
Fraction to Decimal ConversionLong DivisionTerminating Decimals
Fraction to Decimal Conversion
Converting a fraction into a decimal involves dividing the numerator by the denominator. This transformation helps to express values in decimal form, which is often more intuitive for calculations. When we convert fractions like \( \frac{7}{9} \), this process involves quite simple arithmetic. The key is performing the division of 7 by 9. Here, since 7 is smaller than 9, we know its decimal equivalent will be less than 1. Using long division or a calculator, we find the decimal result. Often, this step is fundamental to understanding if your fraction's decimal form ends abruptly (making it a terminating decimal) or keeps going in a repeat, indicative of a repeating decimal.
Long Division
Long division is a method used to divide larger numbers that gives you a clearer understanding of the decimal conversion process. It involves a series of smaller, simplified step-by-step calculations that handle one digit of the dividend at a time. Let's see this in action with \( \frac{7}{9} \):
- Start by writing down the division symbol with 7 inside and 9 outside.
- Recognize that 9 does not fit into 7, so begin with a few decimal places.
- Bring down a 0, making it 70. Divide 70 by 9, which equals 7, with 7 as the remainder.
- Repeat this process. You keep bringing down zeros and dividing, noticing that the remainder cycles back, repeating the process indefinitely.
Terminating Decimals
Terminating decimals come to an end after a certain number of digits. They are neat and concise because they eventually stop, unlike repeating decimals that go on forever. This happens when the fraction's denominator can be divided cleanly (after canceling any common factors) into parts of 10 (i.e., 2 or 5 as the prime factors), like \( \frac{1}{2} = 0.5 \).In comparison, a fraction like \( \frac{7}{9} \) has a denominator with a prime factor of 3, which cannot be expressed as a finite decimal. As a result, this fraction converts to an endless decimal string, 0.777... repeatedly, categorizing it as a repeating decimal. Terminating decimals are simpler to work within arithmetic calculations, thanks to their compact nature.
Other exercises in this chapter
Problem 47
At 2 P.M., two military convoys leave Eagle River, Wisconsin, one headed north and one headed south. The convoy headed north averages \(50 \mathrm{mph}\), and t
View solution Problem 47
Solve each equation. Check each result. See Example 5. $$ 3(k-4)=-36 $$
View solution Problem 47
Graph each set on a number line. $$ \left\\{-\frac{5}{2},-0.1,2.142765 \ldots, \frac{\pi}{3},-\sqrt{11}, 2 \sqrt{3}\right\\} $$
View solution Problem 47
Write a mathematical model for each situation. Answers may vary depending on the variables chosen. Taxes. \(\quad\) A married couple has decided to split the mo
View solution