Problem 47
Question
When computations are carried out on a calculator, the quadratic formula will not always give accurate results if \(b^{2}\) is large in comparison to \(a c,\) because one of the roots will be close to zero and difficult to approximate. (a) Use the quadratic formula to approximate the roots of the given equation. (b) To obtain a better approximation for the root near zero, rationalize the numerator to change $$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} \text { to } x=\frac{2 c}{-b \mp \sqrt{b^{2}-4 a c}},$$ and use the second formula. $$x^{2}+4,500,000 x-0.96=0$$
Step-by-Step Solution
Verified Answer
Use the rationalized formula for a small root: \( x \approx -2.13 \times 10^{-7} \) for accuracy.
1Step 1: Identify the coefficients
Given the quadratic equation \( x^2 + 4,500,000x - 0.96 = 0 \), identify the coefficients as follows: \( a = 1 \), \( b = 4,500,000 \), and \( c = -0.96 \).
2Step 2: Use the standard quadratic formula
The quadratic formula is given by \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). Substitute the coefficients into this formula:\[x = \frac{-4,500,000 \pm \sqrt{(4,500,000)^2 - 4 \times 1 \times (-0.96)}}{2 \times 1}\]
3Step 3: Simplify inside the square root
Calculate the discriminant \( b^2 - 4ac \):\[(4,500,000)^2 - 4 \times 1 \times (-0.96) = 20,250,000,000,003.84\]
4Step 4: Calculate square root and roots
Find \( \sqrt{20,250,000,000,003.84} \) and substitute back into the quadratic formula to solve for both roots:\[x = \frac{-4,500,000 \pm \sqrt{20,250,000,000,003.84}}{2}\]This will yield two roots: a large positive value and a very small negative value.
5Step 5: Rationalize the numerator
To find the root near zero, use the alternative formula: \[x = \frac{2c}{-b \mp \sqrt{b^2 - 4ac}}\]Substitute \( c = -0.96 \), \( b = 4,500,000 \), and \( \sqrt{b^2 - 4ac} = \sqrt{20,250,000,000,003.84} \) to get:\[x = \frac{2 \times -0.96}{-4,500,000 + \sqrt{20,250,000,000,003.84}}\]
6Step 6: Calculate the root using the rationalized formula
Perform the division with the rationalized formula to approximate the root close to zero. The alternative formula provides a more accurate small root approximation compared to the standard quadratic formula.
Key Concepts
Understanding the Quadratic FormulaRole of the Discriminant in Quadratic EquationsRationalizing Expressions to Enhance Accuracy
Understanding the Quadratic Formula
The quadratic formula is a powerful mathematical tool which helps find the roots, or solutions, of quadratic equations. A quadratic equation is typically written in the form \(ax^2 + bx + c = 0\). Here, \(a\), \(b\), and \(c\) are coefficients, where \(a\) cannot be zero. The formula for finding the roots of this equation is:
In many scenarios, the roots calculated using this formula can either be both real, or one of them can be close to zero. Calculating such small roots accurately is important, especially when dealing with quite large values of \(b\), as in our given equation.
- \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
In many scenarios, the roots calculated using this formula can either be both real, or one of them can be close to zero. Calculating such small roots accurately is important, especially when dealing with quite large values of \(b\), as in our given equation.
Role of the Discriminant in Quadratic Equations
The discriminant is a specific part of the quadratic formula under the square root, \(b^2 - 4ac\). It helps determine the nature of the roots of a quadratic equation. By examining the value of the discriminant, you can tell whether the roots are real and distinct, real and equal, or complex.
- If \(b^2 - 4ac > 0\), the equation has two distinct real roots.
- If \(b^2 - 4ac = 0\), the equation has exactly one real root, also known as a repeated root.
- If \(b^2 - 4ac < 0\), the equation has two complex roots.
Rationalizing Expressions to Enhance Accuracy
Rationalizing expressions are often used in mathematical calculations to simplify expressions or calculations that involve square roots. In the context of quadratic equations, rationalizing the numerator can lead to more accurate results, especially when solving for roots that are very small or very large.
Here, we altered the quadratic formula from:
Here, we altered the quadratic formula from:
- \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
- \(x = \frac{2c}{-b \mp \sqrt{b^2 - 4ac}}\)
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Problem 46
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