Problem 47
Question
Verify the Identity. $$\ln \cot x=-\ln \tan x$$
Step-by-Step Solution
Verified Answer
The identity \( \ln \cot x = -\ln \tan x \) is verified as both sides simplify to \( \ln \cos x - \ln \sin x \).
1Step 1: Express Cotangent and Tangent in Terms of Sine and Cosine
We know that \( \cot x = \frac{\cos x}{\sin x} \) and \( \tan x = \frac{\sin x}{\cos x} \). Replacing \( \cot x \) in the equation gives \( \ln \left( \frac{\cos x}{\sin x} \right) \).
2Step 2: Use the Logarithm Property on Cotangent
Using the property \( \ln \left( \frac{a}{b} \right) = \ln a - \ln b \), we can rewrite \( \ln \left( \frac{\cos x}{\sin x} \right) \) as \( \ln \cos x - \ln \sin x \).
3Step 3: Rewrite the Right Side Using Tangent Expression
Remembering that \( \tan x = \frac{\sin x}{\cos x} \), substitute into \( -\ln \tan x \) to get \( -\ln \left( \frac{\sin x}{\cos x} \right) \).
4Step 4: Apply Logarithm Property to the Negation
Using the logarithm property, \( -\ln \left( \frac{\sin x}{\cos x} \right) = - (\ln \sin x - \ln \cos x) \), which simplifies to \( -\ln \sin x + \ln \cos x \).
5Step 5: Compare Both Sides of the Identity
Both sides simplify to \( \ln \cos x - \ln \sin x \), verifying that \( \ln \cot x = -\ln \tan x \) is true.
Key Concepts
Trigonometric IdentitiesProperties of LogarithmsTrigonometric Functions
Trigonometric Identities
Trigonometric identities are mathematical statements that equate one expression to another in terms of trigonometric functions. They are essential tools in simplifying complex expressions and solving trigonometric equations. To understand these identities, consider some fundamental ones like the Pythagorean identity, which states \(\sin^2 x + \cos^2 x = 1\). This helps in transforming and verifying expressions.
In the exercise, the identity being verified involves \(\cot x\) and \(\tan x\), which are the reciprocals of tangent and cotangent functions respectively. The goal here is to express the original identity \(\ln \cot x = -\ln \tan x\) in alternative formats that reveal their equivalence.
In the exercise, the identity being verified involves \(\cot x\) and \(\tan x\), which are the reciprocals of tangent and cotangent functions respectively. The goal here is to express the original identity \(\ln \cot x = -\ln \tan x\) in alternative formats that reveal their equivalence.
- The cotangent function, \(\cot x\), is expressed as \(\frac{\cos x}{\sin x}\).
- The tangent function, \(\tan x\), is expressed as \(\frac{\sin x}{\cos x}\).
Properties of Logarithms
Logarithms have specific properties that make them incredibly useful for simplifying expressions. These properties allow operations such as multiplication, division, and powers to be expressed in a simplified logarithmic form. Let's explore a couple of key properties:
- Product Property: \(\ln ab = \ln a + \ln b\)
- Quotient Property: \(\ln \left(\frac{a}{b}\right) = \ln a - \ln b\)
- Power Property: \(\ln a^b = b \ln a\)
Trigonometric Functions
Trigonometric functions, such as sine, cosine, tangent, cotangent, secant, and cosecant, describe the relationships between the angles and sides of a right triangle. They are periodic, which means they repeat their values in regular intervals, making them cornerstone functions in trigonometry.
Each trigonometric function can be defined using a unit circle. For instance, the sine and cosine functions are linked to the vertical and horizontal positions of a point rotating around the circle. These functions are fundamental in expressing other trigonometric functions:
Each trigonometric function can be defined using a unit circle. For instance, the sine and cosine functions are linked to the vertical and horizontal positions of a point rotating around the circle. These functions are fundamental in expressing other trigonometric functions:
- \(\sin x = \text{opposite} / \text{hypotenuse}\) in a right triangle.
- \(\cos x = \text{adjacent} / \text{hypotenuse}\) in a right triangle.
- \(\tan x = \sin x / \cos x\)
- \(\cot x = 1 / \tan x = \cos x / \sin x\)
Other exercises in this chapter
Problem 46
Find the solutions of the equation that are in the interval \([0,2 \pi)\). $$\sec \beta \csc \beta=2 \csc \beta$$
View solution Problem 47
Solve the equation for \(x\) in terms of \(y\) if \(x\) is restricted to the given interval. $$y=-3-\sin x ; \quad\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$$
View solution Problem 47
Express \(\sin (u+v+w)\) in terms of trigonometric functions of \(u, v,\) and \(w .\) (Hint: Write $$ \sin (u+v+w) \text { as } \sin [(u+v)+w] $$ and use additi
View solution Problem 47
Find the solutions of the equation that are in the interval \([0,2 \pi)\). $$2 \cos ^{2} \gamma+\cos \gamma=0$$
View solution