Problem 47
Question
Solve the inequality. Then graph the solution set on the real number line. \(1<2 x+3<9\)
Step-by-Step Solution
Verified Answer
The solution set for the inequality is \(-1
1Step 1: Solving the first inequality
To isolate \(x\) in the first inequality \(1<2x+3\), first subtract 3 from both sides. This gives us \(-2<2x\). Then divide each part by 2. The resulting inequality is \(-1
2Step 2: Solving the second inequality
To isolate \(x\) in the second inequality \(2x+3<9\), subtract 3 from both sides, which gives \(2x<6\). Dividing each side by 2, we get \(x<3\).
3Step 3: Determining the common solution
The solutions to the two inequalities that were obtained (\(-1
4Step 4: Graphing the solution
The graph of the solution is a line segment on the number line between -1 and 3 (not including -1 and 3). It can be represented with an open circle at -1 and 3, and a line connecting these two points.
Key Concepts
Graphing on the number lineCompound inequalitiesSolving linear inequalities
Graphing on the number line
When we talk about graphing on the number line, it is an excellent way to visually represent the solution to an inequality. A number line gives us a linear perspective of the values that satisfy an inequality.
In the problem, we solved the compound inequality, which gave us two components: \(-1 < x < 3\). To graph this solution:
In the problem, we solved the compound inequality, which gave us two components: \(-1 < x < 3\). To graph this solution:
- Draw a horizontal line and mark evenly spaced numbers on it, including -1 and 3.
- Since -1 and 3 are not part of the solution (the inequality is strict), we represent them with open circles on the number line.
- Draw a line connecting these open circles to show all the values between -1 and 3 are valid solutions.
Compound inequalities
Compound inequalities involve two separate inequalities that are connected by an "and" or an "or". In our case, the problem used "and", which means we want values of \(x\) that satisfy both inequalities at the same time.
Here's how compound inequalities work:
Here's how compound inequalities work:
- Each part of the inequality is solved separately. In our example, this means solving \(-1 < x\) and \(x < 3\).
- We then find the intersection of these solutions. In other words, we look for the values of \(x\) that make both inequalities true.
Solving linear inequalities
The process of solving linear inequalities is very similar to solving equations, but with a key difference: when you multiply or divide by a negative number, you must reverse the direction of the inequality sign.
For solving a simple linear inequality:
For solving a simple linear inequality:
- Perform the same operations on each side of the inequality as you would with an equation to isolate the variable.
- For the given inequality \(1 < 2x + 3 < 9\), handle each part separately, simplifying step-by-step.
- Subtract or add quantities across the inequality to zero out constants next to the variable.
- Finally, divide or multiply to solve for the variable, keeping in mind to flip the inequality sign if dividing or multiplying by a negative number, although this did not occur in our specific problem.
Other exercises in this chapter
Problem 46
Solve the equation and check your solution. (Some equations have no solution.) $$ \frac{4}{u-1}+\frac{6}{3 u+1}=\frac{15}{3 u+1} $$
View solution Problem 47
Consider the domains of the expressions \(\sqrt[3]{x^{2}-7 x+12}\) and \(\sqrt{x^{2}-7 x+12}\). Explain why the domain of \(\sqrt[3]{x^{2}-7 x+12}\) consists of
View solution Problem 47
Find the real solution(s) of the equation involving fractions. Check your solutions. \(\frac{4}{x+1}-\frac{3}{x+2}=1\)
View solution Problem 47
Writing Real-Life Problems In Exercises 47-50, solve the number problem and write a real-life problem that could be represented by this verbal model. For instan
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