Problem 47
Question
Radioactive Decay. Five hundred grams of a radioactive material decays according to the formula \(A=500\left(\frac{2}{3}\right)^{t},\) where \(t\) is measured in years. Find the amount present in 10 years. Round to the nearest one-tenth of a gram.
Step-by-Step Solution
Verified Answer
The amount present in 10 years is approximately 8.7 grams.
1Step 1: Understand the given formula
The formula for radioactive decay is given by \( A = 500 \left( \frac{2}{3} \right)^{t} \). Here, \( A \) is the amount of substance present at time \( t \), \( 500 \) is the initial amount of substance, and \( \left( \frac{2}{3} \right)^{t} \) represents the decay over time. The value \( t \) is the time in years.
2Step 2: Substitute the time value
We need to find the amount present after 10 years, which means we will substitute \( t = 10 \) into the formula. This gives:\[ A = 500 \left( \frac{2}{3} \right)^{10} \]
3Step 3: Calculate the decay factor raised to the power of time
Calculate \( \left( \frac{2}{3} \right)^{10} \). This is a repeated multiplication:\[ \left( \frac{2}{3} \right) \times \left( \frac{2}{3} \right) \times \cdots \text{(a total of 10 times)} \approx 0.01734 \]
4Step 4: Multiply to find the remaining amount
Multiply the initial amount by the decay factor:\[ A = 500 \times 0.01734 \approx 8.67 \]
5Step 5: Round the result
Round 8.67 to the nearest one-tenth of a gram, which gives us 8.7 grams.
Key Concepts
Exponential Decay FormulaRadioactive MaterialDecay Calculation
Exponential Decay Formula
The exponential decay formula is essential in understanding how quantities reduce over time. Specifically, for radioactive decay, the formula is expressed as \( A = A_0 imes \left( \frac{x}{y} \right)^t \).
- \( A \) represents the remaining amount of the radioactive material at time \( t \).
- \( A_0 \) is the initial quantity, in our case, 500 grams.
- The fraction \( \left( \frac{x}{y} \right) \) is the decay factor, which determines how quickly the material decays.
- \( t \) is the time period over which the decay occurs.
Radioactive Material
Radioactive materials are substances that emit radiation as they break down or decay. This natural process involves the transformation of an unstable atomic nucleus.
- They can release different types of radiation, such as alpha, beta, or gamma rays.
- Each type of radioactive material decays at a specific rate, expressed mathematically by its half-life.
- The half-life is the time it takes for half of the material to decay, which is central to understanding how the amount decreases over time.
Decay Calculation
Calculating the decay involves determining how much of a radioactive material remains after a certain period. In the given problem, we used the formula \( A = 500 \left( \frac{2}{3} \right)^{10} \) to find this amount after 10 years.
- The decay factor \( \left( \frac{2}{3} \right) \) is raised to the power of \( t \), which in this case is 10.
- This computes the repeated multiplication, simulating the decay over the years. The result was approximately \( 0.01734 \).
- Finally, multiplying the original quantity (500 grams) by this value gave us \( A \approx 8.67 \).
- Rounding \( 8.67 \) to the nearest one-tenth of a gram resulted in \( 8.7 \) grams remaining.
Other exercises in this chapter
Problem 46
Write logarithm as the sum and/or difference of logarithms of a single quantity. Then simplify, if possible. \(\log _{2} \frac{a b}{4}\)
View solution Problem 47
Evaluate each expression without using a calculator. $$ \ln \sqrt[4]{e} $$
View solution Problem 47
Each of the following functions is one-to-one. Find the inverse of each function and express it using \(f^{-1}(x)\) notation. \(f(x)=\sqrt[3]{x}\)
View solution Problem 47
Write logarithm as the sum and/or difference of logarithms of a single quantity. Then simplify, if possible. \(\ln \frac{e x y}{z}\)
View solution