Problem 47
Question
Let \(X\) be exponentially distributed with parameter \(\lambda\). Find \(E(X)\)
Step-by-Step Solution
Verified Answer
The expected value of \(X\) is \(\frac{1}{\lambda}\).
1Step 1: Understanding the Exponential Distribution
The exponential distribution is a continuous probability distribution often used to model the time between events. When a random variable \(X\) is exponentially distributed, it is characterized by the parameter \(\lambda > 0\), which is the rate of the distribution.
2Step 2: Recalling the Expected Value Formula for Exponential Distribution
For a random variable \(X\) that is exponentially distributed with parameter \(\lambda\), the expected value \(E(X)\) is given by the formula \(E(X) = \frac{1}{\lambda}\). This is a fundamental property of the exponential distribution, based on its probability density function and moment generating function.
3Step 3: Substituting the Parameter into the Expected Value Formula
Since \(X\) is distributed with parameter \(\lambda\), we use the formula \(E(X) = \frac{1}{\lambda}\) and substitute \(\lambda\) as specified by the distribution of \(X\).
4Step 4: Conclusion
The expected value of an exponentially distributed random variable \(X\) with parameter \(\lambda\) is \(\frac{1}{\lambda}\). Therefore, \(E(X) = \frac{1}{\lambda}\).
Key Concepts
Expected ValueProbability DistributionMoment Generating Function
Expected Value
The expected value of a random variable, often symbolized as \(E(X)\), is a key concept in probability and statistics. It represents the long-term average or mean of a random variable over numerous trials or experiments. For the exponential distribution, the expected value is directly linked to its parameter, \(\lambda\). The exponential distribution is unique because, unlike other distributions, it models the time until the next event occurs, such as the time between arrivals at a service center.
For an exponential distribution with parameter \(\lambda\), the formula for the expected value is relatively straightforward:
For an exponential distribution with parameter \(\lambda\), the formula for the expected value is relatively straightforward:
- \(E(X) = \frac{1}{\lambda}\)
Probability Distribution
A probability distribution is a mathematical function that provides the probabilities of occurrence of different possible outcomes. For continuous random variables, like those following an exponential distribution, this is often represented by a probability density function (PDF).
The exponential probability distribution is defined by its PDF:
Key properties of the exponential distribution include:
The exponential probability distribution is defined by its PDF:
- \(f(x; \lambda) = \lambda e^{-\lambda x}\) for \(x \geq 0\)
Key properties of the exponential distribution include:
- Memoryless property: The probability of an event occurring in the future is independent of any past events.
- Non-negative values: It only takes values from \(0\) to infinity.
Moment Generating Function
The moment-generating function (MGF) is a powerful tool in probability theory. It provides a convenient way to derive the moments of a random variable, such as the mean and variance.
For an exponentially distributed random variable with rate \(\lambda\), the MGF is given by:
The first moment, or the expected value \(E(X)\), can be found by taking the first derivative of the MGF with respect to \(t\) and evaluating at \(t = 0\). This process reaffirms the expected value \(\frac{1}{\lambda}\).
The moment-generating function is especially beneficial because it simplifies working with multiple and independent random variables, helping to combine them into one distribution efficiently. For exponential distributions, it highlights its main properties and aids in underpinning the mathematical applications.
For an exponentially distributed random variable with rate \(\lambda\), the MGF is given by:
- \(M_X(t) = \frac{\lambda}{\lambda - t}\) for \(t < \lambda\)
The first moment, or the expected value \(E(X)\), can be found by taking the first derivative of the MGF with respect to \(t\) and evaluating at \(t = 0\). This process reaffirms the expected value \(\frac{1}{\lambda}\).
The moment-generating function is especially beneficial because it simplifies working with multiple and independent random variables, helping to combine them into one distribution efficiently. For exponential distributions, it highlights its main properties and aids in underpinning the mathematical applications.
Other exercises in this chapter
Problem 46
In how many ways can two aces and three kings be selected from a standard deck of cards if cards are drawn without replacement?
View solution Problem 47
An urn contains 12 green and 24 blue balls. (a) You take 10 balls out of the urn without replacing them. Find the probability that 6 of the 10 balls are blue. (
View solution Problem 47
Thirteen cards are drawn at random without replacement from a standard deck of 52 cards. What is the probability that all are red?
View solution Problem 47
In the game of poker, determine the number of ways exactly two pairs can be picked.
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