Problem 47
Question
In Exercises 9-50, verify the identity \( \tan(\sin^{-1} x) = \dfrac{x}{\sqrt{1- x^2}} \)
Step-by-Step Solution
Verified Answer
The given identity \( \tan(\sin^{-1} x) = \dfrac{x}{\sqrt{1- x^2}} \) is proven to be correct through the process of expressing the terms as sides of right triangles and manipulating them using the Pythagorean theorem and definitions of trigonometric functions.
1Step 1: Start With the Left Side
We begin with the left side of the identity that is, \( \tan(\sin^{-1} x) \). We can consider \( \sin^{-1} x = y \), then we have \( \sin y = x \). we obtain a right triangle with the opposite side as x and hypotenuse as 1 by using the definition of sine in a right triangle.
2Step 2: Calculate Adjacent Side
In a right triangle, the side adjacent to the angle in consideration (y in this case) is calculated using the Pythagorean theorem. Let's denote the adjacent side as 'b', then using Pythagorean theorem we get \( b = \sqrt{1^2 - x^2} = \sqrt{1- x^2} \).
3Step 3: Calculate Tangent
We know that the tangent of an angle in a right triangle is the ratio of the length of the opposite side to the adjacent side. Therefore, \( \tan y =\dfrac{x}{\sqrt{1 - x^2}} \).
4Step 4: Back-substitute
Substitute \( y = \sin^{-1} x \) back into the equation. Hence, \( \tan(\sin^{-1} x) = \dfrac{x}{\sqrt{1- x^2}} \), which is the right side of the original equation. Hence the identity is verified.
Key Concepts
Inverse Trigonometric FunctionsPythagorean TheoremTangent in Right Triangles
Inverse Trigonometric Functions
Inverse trigonometric functions are the reverse operations of the basic trigonometric functions like sine, cosine, and tangent. For example, the inverse sine function, denoted as \( \sin^{-1}(x) \), gives you an angle whose sine is \( x \).
This is particularly useful when you need to find angles in right triangles. Instead of questioning what the sine of an angle is, you find the angle itself. This forms the basis for many applications in geometry and calculus.
This is particularly useful when you need to find angles in right triangles. Instead of questioning what the sine of an angle is, you find the angle itself. This forms the basis for many applications in geometry and calculus.
- Range for \( \sin^{-1}(x) \): The values of inverse sine are typically between \( -\frac{\pi}{2} \) and \( \frac{\pi}{2} \).
- Useful in Angles: Helps determine angles when two sides' lengths are known.
- Common Notation Variations: Sometimes written as \( \arcsin(x) \).
Pythagorean Theorem
The Pythagorean theorem is a cornerstone of geometry, relating the lengths of sides in a right triangle. Simply put, it states that the square of the hypotenuse (the side opposite the right angle) equals the sum of the squares of the other two sides.
Mathematically, it's expressed as:
\[ a^2 + b^2 = c^2 \] In trigonometric identities, the theorem helps find unknown side lengths, ensuring clarity when determining ratios like sine, cosine, and tangent.
Mathematically, it's expressed as:
\[ a^2 + b^2 = c^2 \] In trigonometric identities, the theorem helps find unknown side lengths, ensuring clarity when determining ratios like sine, cosine, and tangent.
- Hypotenuse Identification: Vital for correct application of the theorem.
- Applications: Supports calculation of side lengths when two sides are known.
- Simplification: Often simplifies complex trigonometric problems into manageable components.
Tangent in Right Triangles
The concept of tangent in right triangles is tied to the relationship between the triangle’s sides. The tangent of an angle \( \theta \) is defined as the ratio of the opposite side to the adjacent side. This function is an essential part of trigonometry and crucial for understanding various angles and lengths.
The formula for tangent is:
\[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} \]In verifying trigonometric identities, knowing how to express tangent in terms of sine and cosine is invaluable.
The formula for tangent is:
\[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} \]In verifying trigonometric identities, knowing how to express tangent in terms of sine and cosine is invaluable.
- Opposite/Adjacent Sides: Clarifies which sides are used in the tangent ratio.
- Paves Way for Identities: Enables conversion between different trigonometric expressions.
- Real-World Applications: Crucial for solving practical problems involving angles.
Other exercises in this chapter
Problem 47
In Exercises \(43-50\) , find the exact value of the trigonometric function given that \(\sin u=\frac{5}{13}\) and \(\cos v=-\frac{3}{5} .\) Both \(u\) and \(v\
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In Exercises 45-48, find the \( x \)-intercepts of the graph. \( y = \tan^2 \left(\dfrac{\pi x}{6} \right) - 3 \)
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In Exercises 37 - 58, use the fundamental identities to simplify the expression. There is more than one correct form of each answer. \( \dfrac{\tan \theta \cot
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Exercises 43-52, use the power-reducing formulas to rewrite the expression in terms of the first power of the cosine. \( \sin^2 x \cos^4 x \)
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