Problem 47

Question

In Exercises \(29-62,\) solve the system of equations using any method you choose. $$\left\\{\begin{array}{l} 5 x-3 y=20 \\ 7 x+2 y=28 \end{array}\right.$$

Step-by-Step Solution

Verified
Answer
The solution is \(x = 4\) and \(y = 0\).
1Step 1 - Choose the method
We'll use the substitution method to solve the system of equations.
2Step 2 - Solve one equation for one variable
Solve the first equation for one of the variables. Let's solve for x.The first equation is: \[5x - 3y = 20\]Rearrange to get x:\[5x = 20 + 3y\]\[x = \frac{20 + 3y}{5}\]
3Step 3 - Substitute into the second equation
Substitute \(x = \frac{20 + 3y}{5}\) into the second equation.The second equation is:\[7x + 2y = 28\]Substitute x:\[7\left(\frac{20 + 3y}{5}\right) + 2y = 28\]
4Step 4 - Simplify the equation
Simplify and solve for y:\[7 \cdot \frac{20 + 3y}{5} + 2y = 28\]\[\frac{140 + 21y}{5} + 2y = 28\]Multiply both sides by 5 to clear the fraction:\[140 + 21y + 10y = 140\]\[31y = 0\]\[y = 0\]
5Step 5 - Solve for x
Substitute y back into the expression for x:\[x = \frac{20 + 3(0)}{5}\]\[x = 4\]
6Step 6 - Check the solution
Substitute \(x = 4\) and \(y = 0\) back into the original equations to ensure they satisfy both equations:First equation:\[5x - 3y = 20\]\[5(4) - 3(0) = 20\]\[20 = 20\]Second equation:\[7x + 2y = 28\]\[7(4) + 2(0) = 28\]\[28 = 28\]Both equations are satisfied.

Key Concepts

substitution methodsolving equationsalgebraic manipulationchecking solutions
substitution method
The substitution method is a powerful tool for solving systems of equations. It involves solving one of the equations for one variable and then substituting this expression into the other equation. This reduces the system to a single equation with one variable, making it easier to solve.
solving equations
Solving equations is the process of finding the value(s) of the variable(s) that make the equation true. In the context of systems of equations, we are looking for a common solution that satisfies all equations in the system.
algebraic manipulation
Algebraic manipulation involves rearranging equations and expressions using algebraic operations such as addition, subtraction, multiplication, and division. This skill is essential when using methods like substitution to isolate variables and solve systems of equations.
checking solutions
Checking solutions ensures that the values obtained for the variables actually satisfy all original equations. This step is crucial to confirm the accuracy of the solution. By substituting the values back into the original equations, we can verify that each one holds true.