Problem 47
Question
In each of Exercises \(45-50\) use the Chain Rule repeatedly to determine the derivative with respect to \(x\) of the given expression. $$ \cos ^{3}(2 x) $$
Step-by-Step Solution
Verified Answer
The derivative is \(-6(\cos(2x))^2 \sin(2x)\).
1Step 1: Identify the Outer and Inner Functions
The expression given is \( \cos^3(2x) \). Here, the outer function is \( u^3 \), where \( u = \cos(2x) \). The inner function is \( \cos(2x) \). Another inner function of \( \cos(2x) \) is \( 2x \).
2Step 2: Differentiating the Outer Function
Firstly, find the derivative of the outer function with respect to \( u \). The derivative of \( u^3 \) is \( 3u^2 \).
3Step 3: Differentiate the Middle Function
Next, differentiate the inner function \( \cos(2x) \) with respect to \( 2x \). The derivative of \( \cos(v) \) with respect to \( v \) is \( -\sin(v) \), hence the derivative of \( \cos(2x) \) is \( -\sin(2x) \).
4Step 4: Differentiate the Innermost Function
Finally, differentiate the innermost function \( 2x \) with respect to \( x \). The derivative is \( 2 \).
5Step 5: Apply the Chain Rule
Applying the chain rule, multiply all the above results. \( \frac{d}{dx}[\cos^3(2x)] = \frac{d}{du}[u^3] \times \frac{d}{dv}[\cos(2x)] \times \frac{d}{dx}[2x] = 3(\cos(2x))^2 (-\sin(2x)) \times 2 \).
6Step 6: Simplify the Expression
Simplify the expression from Step 5: \(= -6(\cos(2x))^2 \sin(2x) \). This is the derivative of \( \cos^3(2x) \) with respect to \( x \).
Key Concepts
Understanding the DerivativeWhat is an Outer Function?Exploring the Inner FunctionHow Differentiation Works
Understanding the Derivative
The concept of a derivative can be thought of as the mathematical equivalent of finding out how something changes. In simple terms, it's a measure of how a function's output value changes as its input value changes. Imagine when you are driving a car on a straight road; the speedometer shows how your position changes over time.
The derivative of a function indicates its rate of change:
The derivative of a function indicates its rate of change:
- If a function is changing quickly, its derivative will have a larger value.
- If the function is not changing, its derivative will be zero.
What is an Outer Function?
In the realm of the chain rule, distinguishing between the outer and inner functions becomes essential. The outer function is essentially the function that appears on the outside of the given composition. In our initial exercise with the expression \( ext{cos}^3(2x)\), think of the outer function as the container or wrapper around the other functions; this is \(u^3\) as \(u = \text{cos}(2x)\).
- Outer functions are usually the last operations applied to whatever expression you're evaluating.
- In expressions like \((...)^n\), the power function tends to be the outer function.
Exploring the Inner Function
The inner function in a problem like this resides within another function. For our expression \( ext{cos}^3(2x)\), the inner function is \( ext{cos}(2x)\). An inner function determines what the outer function operates on.
- In terms of layers, the inner function resides deeper within the original formula.
- After the innermost functions, the next layer of our function tree involves the direct operation on the variable \(x\).
How Differentiation Works
Differentiation is the process of finding a derivative. Essentially, it involves calculating how the output of a particular function changes with respect to a particular input variable. Using the chain rule to differentiate composite functions helps make complex differentiation easier by breaking it down into manageable parts.
The process usually requires three steps:
The process usually requires three steps:
- Identify and differentiate the outer function.
- Find the derivative of the inner function.
- Multiply the derivatives according to the chain rule.
Other exercises in this chapter
Problem 47
Show that the tangent lines to the curve \(x^{2}-4 x y+y^{2}=9\) at the points where the curve crosses the \(x\) -axis are parallel.
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Find a function whose derivative is the given function. \(-8 \csc ^{2}(x)\)
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Describes the position of an object at time \(t\). Calculate the instantaneous velocity at time \(c\). $$ p(t)=t^{2}(3-2 / t) \quad c=3 $$
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