Problem 47
Question
Find the x-intercepts and the y-intercepts of the line. Graph the equation. Label the points where the line crosses the axes. $$ -9 x+y=36 $$
Step-by-Step Solution
Verified Answer
The x-intercept of the line is at point (-4,0) and the y-intercept is at point (0,36).
1Step 1: Find the x-intercept
To find the x-intercept, set \(y = 0\) in the given equation and solve for x. So, \(-9x + 0 = 36\) reduces to \(x = -36 / 9 = -4\). The x-intercept is at the point (-4, 0).
2Step 2: Find the y-intercept
To find the y-intercept, set \(x = 0\) in the equation and then solve for y. So, \(-9 * 0 + y = 36\) reduces to \(y = 36\). Hence, the y-intercept is at the point (0, 36).
3Step 3: Graphing and Labeling
Plot the x-intercept and y-intercept on a graph, draw a straight line through these two points. The point at which the line crosses the X-axis is the x-intercept, and where it crosses the Y-axis is the y-intercept. So, label the point (-4,0) as the x-intercept and (0, 36) as the y-intercept.
Key Concepts
Understanding the X-InterceptDetermining the Y-InterceptGraphing Linear Equations
Understanding the X-Intercept
The x-intercept of a line is the point where the line crosses the x-axis of a graph. Typically, this is the spot where the value of y is zero.
Think of it as the line's way of saying hello to the x-axis! In mathematical terms, to determine the x-intercept from an equation, we set \( y = 0 \) and solve for \( x \).
In our exercise, the equation \( -9x + y = 36 \) becomes \( -9x + 0 = 36 \) when \( y \) is zero.
By solving \( -9x = 36 \), we find that \( x = -4 \). Thus, the x-intercept is \((-4, 0)\).
Think of it as the line's way of saying hello to the x-axis! In mathematical terms, to determine the x-intercept from an equation, we set \( y = 0 \) and solve for \( x \).
In our exercise, the equation \( -9x + y = 36 \) becomes \( -9x + 0 = 36 \) when \( y \) is zero.
By solving \( -9x = 36 \), we find that \( x = -4 \). Thus, the x-intercept is \((-4, 0)\).
- To find the x-intercept, set \( y = 0 \) in the equation.
- Solve for \( x \) to locate the intercept point on the x-axis.
Determining the Y-Intercept
The y-intercept of a line represents the point where the line meets the y-axis. This intersection occurs when the value of \( x \) is zero.
Imagine it as the starting point of your line on the y-axis.
To find the y-intercept in an equation, set \( x = 0 \) and solve for \( y \). In our example \( -9x + y = 36 \), letting \( x \) be zero simplifies it to \( 0 + y = 36 \).
The answer is \( y = 36 \), giving us a y-intercept at \((0, 36)\).
Imagine it as the starting point of your line on the y-axis.
To find the y-intercept in an equation, set \( x = 0 \) and solve for \( y \). In our example \( -9x + y = 36 \), letting \( x \) be zero simplifies it to \( 0 + y = 36 \).
The answer is \( y = 36 \), giving us a y-intercept at \((0, 36)\).
- Set \( x = 0 \) to find the y-intercept.
- Calculate \( y \) for the intercept position on the y-axis.
Graphing Linear Equations
Graphing linear equations involves plotting points where the line interacts with the axes, creating a visual representation of the equation.
First, plotting the x-intercept and the y-intercept provides two exact points through which the line will pass.
In our case, these points are \((-4, 0)\) and \((0, 36)\). Place these points on graph paper or graphing software.
Next, connect them with a straight line, ensuring it extends across the graph.
First, plotting the x-intercept and the y-intercept provides two exact points through which the line will pass.
In our case, these points are \((-4, 0)\) and \((0, 36)\). Place these points on graph paper or graphing software.
Next, connect them with a straight line, ensuring it extends across the graph.
- Plot the x-intercept \((-4, 0)\) on the graph.
- Plot the y-intercept \( (0, 36)\) on the graph.
- Draw a straight line through these points to represent the equation.
Other exercises in this chapter
Problem 46
Use a table of values to graph the equation. $$ y-4 x=-1 $$
View solution Problem 47
Find the slope of the graph of the linear function f. $$ f(0)=4, f(4)=0 $$
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In Exercises 46 and 47, solve the equation for y. (Lesson 3.7) $$ 3 x+12=5(x+y) $$
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Solve the equation. $$ x-(-2)=6 $$
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