Problem 47
Question
Find the sum of the infinite geometric series. $$1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\cdots$$
Step-by-Step Solution
Verified Answer
The sum of the series is \( \frac{3}{2} \).
1Step 1: Identify the First Term
Identify the first term of the series, which is the first number in the sequence. For this series, the first term is 1.
2Step 2: Identify the Common Ratio
Determine the common ratio (r) by dividing the second term by the first term. Here, the second term is \( \frac{1}{3} \) and the first term is 1, so the common ratio is \( r = \frac{1}{3} \).
3Step 3: Check the Sum Formula's Applicability
Remember that the sum of an infinite geometric series \( S \) is given by the formula \( S = \frac{a}{1 - r} \), where \( a \) is the first term and \( r \) is the common ratio, provided \(|r| < 1\). Since \( |r| = \frac{1}{3} < 1 \), the formula can be applied.
4Step 4: Apply the Sum Formula
Substitute the identified values into the formula for the sum of the series: \( S = \frac{1}{1 - \frac{1}{3}} \).
5Step 5: Simplify the Expression
Simplify the expression by computing the denominator: \( 1 - \frac{1}{3} = \frac{2}{3} \), so \( S = \frac{1}{\frac{2}{3}} \).
6Step 6: Compute the Sum
Simplify the fraction further by multiplying by the reciprocal of the denominator: \( S = 1 \times \frac{3}{2} = \frac{3}{2} \).
7Step 7: Final Step: State the Result
Therefore, the sum of the infinite geometric series is \( \frac{3}{2} \).
Key Concepts
Common RatioSum FormulaFirst Term
Common Ratio
In the context of an infinite geometric series, understanding the concept of the common ratio is crucial. The common ratio, denoted by \( r \), is the factor by which each term in the series is multiplied to obtain the next term. To find the common ratio, divide any term by the preceding term. For example, in the series you provided, the second term is \( \frac{1}{3} \) and the first term is 1. So, the common ratio \( r \) is \( \frac{1}{3} \).
- If \( r > 1 \) or \( r < -1 \), the terms will grow larger in magnitude, causing the series to diverge.
- If \( 0 < |r| < 1 \), the terms get smaller, enabling convergence to a sum.
Sum Formula
To determine the sum of an infinite geometric series, we use the sum formula. For any infinite geometric series where \(|r| < 1\), this sum can be calculated using:\[ S = \frac{a}{1 - r} \]Here, \( S \) is the sum of the series, \( a \) is the first term, and \( r \) is the common ratio.
- The condition \(|r| < 1\) ensures that the series converges, making it possible to find a finite sum.
- If \( |r| \geq 1 \), the series does not converge, and so does not have a sum in the conventional sense.
First Term
Identifying the first term, \( a \), of a geometric series establishes the starting point of the sequence. This term is crucial not only in determining the progression of the series but also in calculating the sum when using the sum formula.In your example, the first term \( a \) is 1, which is evident as it is the initial value in the sequence \(1, \frac{1}{3}, \frac{1}{9}, \frac{1}{27}, \ldots\).
- The first term is vital in the sum formula \( S = \frac{a}{1 - r} \) as it directly influences the result of the series' sum.
- A different first term fundamentally changes the sequence and thus the sum of the series.
Other exercises in this chapter
Problem 46
Find the sum. $$\sum_{i=1}^{3} i 2^{i}$$
View solution Problem 47
Show that \(\left(\begin{array}{l}n \\\ 1\end{array}\right)=\left(\begin{array}{c}n \\ n-1\end{array}\right)=n\)
View solution Problem 47
Use a graphing calculator to evaluate the sum. $$\sum_{k=1}^{10} k^{2}$$
View solution Problem 48
A partial sum of an arithmetic sequence is given. Find the sum. $$-10-9.9-9.8-\dots-0.1$$
View solution