Problem 47
Question
Find the horizontal and vertical asymptotes for the graphs of the indicated functions. Then sketch their graphs. $$ g(x)=\frac{14}{2 x^{2}+7} $$
Step-by-Step Solution
Verified Answer
No vertical asymptotes; horizontal asymptote is \( y = 0 \).
1Step 1: Identify Vertical Asymptotes
Vertical asymptotes occur where the denominator is zero and the expression is undefined. For the function \( g(x) = \frac{14}{2x^2 + 7} \), we need to solve \( 2x^2 + 7 = 0 \). However, since \( 2x^2 + 7 \) is always positive for all real \( x \), as \( 2x^2 \) is always non-negative and adds to 7, there are no real values of \( x \) making this zero. Thus, there are no vertical asymptotes.
2Step 2: Identify Horizontal Asymptotes
Horizontal asymptotes are determined by comparing the degrees of the numerator and the denominator. Here, the degree of the numerator (0) is less than the degree of the denominator (2). When the numerator's degree is less than the denominator's, the horizontal asymptote is \( y = 0 \). Thus, the horizontal asymptote is \( y = 0 \).
3Step 3: Sketching the Graph
To sketch the graph, note the function approaches \( y = 0 \) as \( x \) becomes very large or very small (positive or negative infinity), due to the horizontal asymptote. Since there are no vertical asymptotes, the function is smooth and continuous across all x-values. The graph will be symmetric around the y-axis because \( g(x) \) is an even function. Consider evaluating at some key points to further illustrate the curve's behavior.
Key Concepts
Vertical AsymptotesHorizontal AsymptotesFunction GraphingEven Functions
Vertical Asymptotes
In calculus and algebra, vertical asymptotes occur where a rational function becomes undefined. This usually happens when the denominator is set to zero. For our function, \( g(x) = \frac{14}{2x^2 + 7} \), this would require solving \( 2x^2 + 7 = 0 \) to find any real values of \( x \) that make it zero. However, this equation has no real solutions because \( 2x^2 + 7 \) is always positive for all real \( x \). Therefore, this function does not have any vertical asymptotes. This means that the graph of the function will not exhibit any infinite spikes or breaks, ensuring a smooth curve across its domain.
Horizontal Asymptotes
A horizontal asymptote refers to a horizontal line that a graph approaches as \( x \) heads towards infinity or negative infinity. To find horizontal asymptotes of a function, we compare the degrees of the polynomial in the numerator and the denominator. For \( g(x) = \frac{14}{2x^2 + 7} \):
- The degree of the numerator is 0, since it is a constant \( (14) \).
- The degree of the denominator is 2, given by \( 2x^2 \).
Function Graphing
Graphing the function \( g(x) = \frac{14}{2x^2 + 7} \) involves identifying its behavior as it relates to asymptotes and any key characteristics, like symmetry. Since the horizontal asymptote is \( y = 0 \), the graph gets closer to this line but never touches it as \( x \) becomes very large in the positive or negative direction.
Additionally, with no vertical asymptotes, the function is defined for all real numbers, meaning the graph will have no breaks or jumps.
When sketching, plotting some points can further showcase the nature of the curve. Consider evaluating the function at different values of \( x \) to get a better idea of the graph's shape.
Additionally, with no vertical asymptotes, the function is defined for all real numbers, meaning the graph will have no breaks or jumps.
When sketching, plotting some points can further showcase the nature of the curve. Consider evaluating the function at different values of \( x \) to get a better idea of the graph's shape.
Even Functions
Even functions are symmetrical about the y-axis. Mathematically, a function \( f(x) \) is even if \( f(x) = f(-x) \) for all \( x \) in its domain. For \( g(x) = \frac{14}{2x^2 + 7} \), substituting \( -x \) for \( x \) does not change the value of the function:
- \( g(-x) = \frac{14}{2(-x)^2 + 7} = \frac{14}{2x^2 + 7} = g(x) \)
Other exercises in this chapter
Problem 47
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, find each of the right-hand and left-hand limits or state that they do not exist. $$ \lim _{x \rightarrow 0^{-}} \frac{x}{|x|} $$
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Determine whether the function is continuous at the given point \(c .\) If the function is not continuous, determine whether the discontinuity is removable or n
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