Problem 47
Question
Find the first and second derivatives of the functions. $$r=\frac{(\theta-1)\left(\theta^{2}+\theta+1\right)}{\theta^{3}}$$
Step-by-Step Solution
Verified Answer
First derivative: \( \frac{3}{\theta^4} \); Second derivative: \( \frac{-12}{\theta^5} \).
1Step 1: Rewrite the Function in an Easier Form
Let's rewrite the given function for easier differentiation. The function given is: \[ r = \frac{(\theta - 1)(\theta^2 + \theta + 1)}{\theta^3} \]We can split this into two separate functions and simplify the expression by multiplying the terms in the numerator:\[ r = \frac{\theta^3 - \theta^2 + \theta^2 - \theta + \theta - 1}{\theta^3} = \frac{\theta^3 - 1}{\theta^3} \]Divide each term separately:\[ r = 1 - \frac{1}{\theta^3} \]
2Step 2: Find the First Derivative
We will now find the first derivative \( \frac{dr}{d\theta} \) of the simplified function \( r = 1 - \theta^{-3} \).The derivative of a constant (\(1\)) is zero, and the derivative of \( -\theta^{-3} \) using power rule \((d/dx)x^n = nx^{n-1})\) is:\[ \frac{dr}{d\theta} = 0 - (-3)\theta^{-3-1} = 3\theta^{-4} \]Thus:\[ \frac{dr}{d\theta} = \frac{3}{\theta^4} \]
3Step 3: Find the Second Derivative
Now find the second derivative \( \frac{d^2r}{d\theta^2} \) from the first derivative \( \frac{dr}{d\theta} = 3\theta^{-4} \).Applying the power rule \((n\theta^{n-1}))\) again:\[ \frac{d^2r}{d\theta^2} = 3(-4)\theta^{-4-1} = -12\theta^{-5} \]Thus:\[ \frac{d^2r}{d\theta^2} = \frac{-12}{\theta^5} \]
Key Concepts
First DerivativeSecond DerivativePower Rule
First Derivative
The first derivative is a cornerstone in calculus. It helps us understand how a function changes as its input changes.
For the function described here, finding the first derivative means determining the rate at which the function \( r \) changes with respect to \( \theta \).
For the function described here, finding the first derivative means determining the rate at which the function \( r \) changes with respect to \( \theta \).
- Start by simplifying the original function, \( r = \frac{(\theta - 1)(\theta^2 + \theta + 1)}{\theta^3} \), to a more manageable form.
In this case, breaking down the multiplication in the numerator and simplifying it resulted in a function that is easier to derive: \( r = 1 - \theta^{-3} \). - The derivative of \( r \) gives us \( \frac{dr}{d\theta} \). In the simplified form, one term is a constant (\(1\)), and the other is \( -\theta^{-3} \).
Applying the power rule, where \( d/dx(x^n) = nx^{n-1} \), the derivative of \( -\theta^{-3} \) is \( +3\theta^{-4} \).
This means: \[ \frac{dr}{d\theta} = \frac{3}{\theta^4} \]
Second Derivative
The second derivative provides even deeper insights into a function's behavior. Once you have the first derivative, the second derivative shows how the rate of change itself is changing.
Consider the first derivative we found: \( \frac{dr}{d\theta} = 3\theta^{-4} \).
To find the second derivative, we apply the power rule again:
Consider the first derivative we found: \( \frac{dr}{d\theta} = 3\theta^{-4} \).
To find the second derivative, we apply the power rule again:
- Take the derivative of the first derivative using \( n\theta^{n-1} \).
Here, \( 3\theta^{-4} \) becomes \( -12\theta^{-5} \). - The result, \( \frac{d^2r}{d\theta^2} = \frac{-12}{\theta^5} \), helps indicate concavity.
Concavity tells us if the function is curving upwards or downwards at a given \( \theta \).
Power Rule
The power rule is one of the most fundamental rules for differentiation. It's powerful for finding derivatives efficiently, especially in polynomial functions.
In simple terms, if you have a function in the form \( x^n \), the derivative is \( nx^{n-1} \).
In simple terms, if you have a function in the form \( x^n \), the derivative is \( nx^{n-1} \).
- This rule makes differentiating straightforward by reducing the power by one and multiplying the term by the original power.
- In our exercise, use the power rule to derive both the first and second derivatives.
Starting with \( r = 1 - \theta^{-3} \), differentiating \( -\theta^{-3} \) gives you \( +3\theta^{-4} \) using the power rule.
Next, \( 3\theta^{-4} \) is differentiated again to obtain \( -12\theta^{-5} \).
Other exercises in this chapter
Problem 47
The line that is normal to the curve \(x^{2}+2 x y-3 y^{2}=0\) at (1,1) intersects the curve at what other point?
View solution Problem 47
Find the limits. $$\lim _{x \rightarrow 2} \sin \left(\frac{1}{x}-\frac{1}{2}\right)$$
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Use logarithmic differentiation to find the derivative of \(y\) with respect to the given independent variable. $$y=\frac{1}{t(t+1)(t+2)}$$
View solution Problem 48
Which of the expressions are defined, and which are not? Give reasons for your answers. a. \(\cot ^{-1}(-1 / 2)\) b. \(\cos ^{-1}(-5)\)
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