Problem 47
Question
Find the eccentricity \(e\) of each ellipse or hyperbola. $$x^{2}-9 y^{2}=18$$
Step-by-Step Solution
Verified Answer
The eccentricity is \(\frac{\sqrt{10}}{3}\).
1Step 1: Identify the Type of Conic Section
The given equation \(x^2 - 9y^2 = 18\) can be identified as a hyperbola since the terms \(x^2\) and \(y^2\) have opposite signs.
2Step 2: Write the Standard Form of the Hyperbola Equation
The standard form of a hyperbola equation is \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\). To achieve this, divide the given equation \(x^2 - 9y^2 = 18\) by 18. We get \(\frac{x^2}{18} - \frac{y^2}{2} = 1\). Here, \(a^2 = 18\) and \(b^2 = 2\).
3Step 3: Determine the Eccentricity Formula for a Hyperbola
For a hyperbola, the eccentricity \(e\) is given by the formula \(e = \sqrt{1 + \frac{b^2}{a^2}}\).
4Step 4: Plug Values into the Eccentricity Formula
Since \(a^2 = 18\) and \(b^2 = 2\), substitute into the formula: \(e = \sqrt{1 + \frac{2}{18}}\).
5Step 5: Simplify the Expression to Find Eccentricity
Calculate \(\frac{2}{18} = \frac{1}{9}\). Thus, \(e = \sqrt{1 + \frac{1}{9}} = \sqrt{\frac{10}{9}}\). Simplify to find \(e = \frac{\sqrt{10}}{3}\).
Key Concepts
HyperbolaConic SectionsStandard FormMathematical Formula
Hyperbola
A hyperbola is a fascinating shape formed by the intersection of a plane with a double cone. It is part of the family of conic sections, which also includes ellipses, parabolas, and circles. Here's why it's interesting:
- A hyperbola consists of two separate curves that are mirror images of each other.
- The curves open away from each other, unlike an ellipse where they form a single loop.
- Hyperbolas have two axes of symmetry: the transverse and the conjugate axis.
Conic Sections
Conic sections are the curves obtained by intersecting a plane with a cone. The most common conic sections include:
- Circle: A special type of ellipse where both axes are equal.
- Ellipse: An oval shape formed when the plane intersects the cone at an angle less than the opening angle of the cone.
- Parabola: A curve formed when the plane is parallel to the edge of the cone.
- Hyperbola: Formed when the plane cuts through both nappes of the cone.
Standard Form
The standard form of an equation is a way of writing it to reveal its key properties and simplify calculations. For hyperbolas, this is especially helpful because it lays out all necessary components clearly. The general standard form of a hyperbola equation is:\[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \] This form allows mathematicians to easily identify the coefficients, determine the axis orientation, and calculate further properties like the foci and asymptotes. In our exercise, converting the given equation to its standard form was essential to find eccentricity, as it clarified which values to use for further calculations.
Mathematical Formula
Mathematical formulas are the backbone of solving equations, and understanding how to use them is crucial. In our exercise, we dealt with the formula for determining the eccentricity of a hyperbola:\[ e = \sqrt{1 + \frac{b^2}{a^2}} \] This formula helps in quantifying how "stretched" the conic section is. For hyperbolas, the eccentricity is always greater than 1. Smaller values close to 1 indicate a shape closer to a rectangular hyperbola, whereas larger values signify a more elongated form. Understanding which formula to apply, and how to derive values from it, is key to learning successful problem-solving techniques in math.
Other exercises in this chapter
Problem 47
Graph each hyberbola by hand. Give the domain and range. Do not use a calculator. $$\frac{x^{2}}{16}-\frac{y^{2}}{9}=1$$
View solution Problem 47
Decide whether each equation has a circle as its graph. If it does, give the center and radius. $$x^{2}-4 x+y^{2}+12 y=-4$$
View solution Problem 48
Graph each hyberbola by hand. Give the domain and range. Do not use a calculator. $$\frac{y^{2}}{9}-\frac{x^{2}}{9}=1$$
View solution Problem 48
Decide whether each equation has a circle as its graph. If it does, give the center and radius. $$x^{2}-12 x+y^{2}+10 y=-25$$
View solution