Problem 47
Question
Find each special product. $$ (5 b-2)^{2} $$
Step-by-Step Solution
Verified Answer
The expanded form is \(25b^2 - 20b + 4\).
1Step 1: Recognize the Pattern
The expression \((5b - 2)^2\) is a binomial squared. We utilize the formula \((a-b)^2 = a^2 - 2ab + b^2\), where \(a = 5b\) and \(b = 2\). This formula simplifies the squared term.
2Step 2: Apply the Formula for Squaring a Binomial
Substitute \(a = 5b\) and \(b = 2\) into the formula \((a-b)^2 = a^2 - 2ab + b^2\). This gives us:\[(5b - 2)^2 = (5b)^2 - 2(5b)(2) + (2)^2\]
3Step 3: Calculate Each Term Separately
Now, calculate each part of the expression:1. \((5b)^2 = 25b^2\)2. \(-2(5b)(2) = -20b\)3. \((2)^2 = 4\)
4Step 4: Combine the Calculated Terms
Combine the results from Step 3:\[25b^2 - 20b + 4\]
Key Concepts
Understanding Special ProductsSquaring a BinomialExploring Algebraic Expressions
Understanding Special Products
Special products are a notable category in algebra where certain products of binomials have predictable results. Understanding these can simplify computations and problem-solving in algebraic contexts. The key special products formulas include the square of a binomial, the product of binomials, and the difference of squares. These formulas are efficient shortcuts. Instead of expanding expressions manually, you can directly apply the formulas to find the product.
The exercise in question involves recognizing the special product formula used for a squared binomial. Identifying special products is crucial because:
The exercise in question involves recognizing the special product formula used for a squared binomial. Identifying special products is crucial because:
- They save time by skipping lengthy multiplication or FOIL steps.
- They simplify calculations, especially when dealing with complex algebraic expressions.
Squaring a Binomial
Squaring a binomial involves finding the square of an expression of the form \((a-b)^2\) or \((a+b)^2\). It entails a specific algebraic expansion resulting from multiplying the binomial by itself. These formulas help:
- \((a+b)^2 = a^2 + 2ab + b^2\)
- \((a-b)^2 = a^2 - 2ab + b^2\)
- Squaring the first term: \((5b)^2 = 25b^2\)
- Doubling the product of both terms: \(-2(5b)(2) = -20b\)
- Squaring the second term: \((2)^2 = 4\)
Exploring Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and arithmetic operations. They represent generalized instructions for how to calculate numbers. When working with algebraic expressions, particularly in contexts such as the special product, understanding the components is essential.
In our example, the binomial \((5b - 2)\) is an algebraic expression made up of:
Being able to expand, factor, and simplify these expressions is a lifelong mathematical tool, giving you power and flexibility in both pure math and applied contexts, such as physics and engineering.
In our example, the binomial \((5b - 2)\) is an algebraic expression made up of:
- A variable term \(5b\), which involves a coefficient and a variable.
- A constant term \(-2\).
Being able to expand, factor, and simplify these expressions is a lifelong mathematical tool, giving you power and flexibility in both pure math and applied contexts, such as physics and engineering.
Other exercises in this chapter
Problem 46
Factor out the GCF. $$ a^{2}+9 a $$
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The following is a list of random factoring problems. Factor each expression. If an expression is not factorable, write "prime." See Examples 1-5. $$ 18 a^{2}-6
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Factor. If a polynomial can't be factored, write "prime." $$ y^{2}-63 $$
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Solve each equation. $$ 4 y^{2}=12 y $$
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