Problem 47
Question
Find an equation for the parabola that has its vertex at the origin and satisfies the given condition(s). Directrix has \(y\) -intercept 6
Step-by-Step Solution
Verified Answer
The equation is \( x^2 = -24y \).
1Step 1: Understand the Parabola's Properties
We need an equation for a parabola with a vertex at the origin and a directrix at a line with a y-intercept of 6. A parabola is defined as the set of points equidistant from the focus and the directrix. For this exercise, the vertex (0, 0) implies that the parabola opens upwards or downwards since its vertex is at the origin, depending on the position of the directrix.
2Step 2: Determine the Directrix Equation
The directrix is a horizontal line with a y-intercept at 6, so its equation is \( y = 6 \). Since it lies above the vertex at the origin (0,0), the parabola opens downwards.
3Step 3: Determine the Focus
The distance from the vertex to the directrix is half the value needed to find the focus. Since the directrix is \( y = 6 \), the distance to the vertex is 6. Thus, the focus, which is equidistant from the vertex, is at (0, -6) because the parabola opens downwards.
4Step 4: Write the Parabola Equation Form
For a parabola opening vertically, the standard equation is \( x^2 = 4py \), where \( p \) is the distance from the vertex to the focus. Here, \( p = -6 \) as the parabola opens downwards. This means the parabola's equation is \( x^2 = -24y \), because \( 4p = 4(-6) = -24 \).
Key Concepts
Vertex FormDirectrixFocus of a ParabolaConic Sections
Vertex Form
In the world of parabolas, the vertex form is incredibly useful for identifying key features of the parabola, such as the vertex itself. The vertex form of a parabola's equation is written as \( y = a(x-h)^2 + k\), where \( (h, k) \) represents the vertex.
- Here, \( h \) and \( k \) are the x and y coordinates of the vertex.
- For example, a vertex form of \( y = 2(x - 3)^2 + 4 \) indicates a vertex at \( (3, 4) \)
Directrix
The directrix is a fixed line used in defining a parabola. It's a geometric construct that helps in understanding how a parabola is shaped. A parabola can be seen as the locus of points that are equidistant from a fixed point called the **focus** and a line known as the **directrix**.
In our example, the directrix is the line identified by the equation\( y = 6\). It lies above the vertex at \( (0, 0) \), indicating that our parabola opens downwards.
In our example, the directrix is the line identified by the equation\( y = 6\). It lies above the vertex at \( (0, 0) \), indicating that our parabola opens downwards.
- The distance from the vertex to this line helps determine the focus of the parabola
- For every point on the parabola, this distance to the directrix is equal to the distance to the focus.
Focus of a Parabola
The focus of a parabola is key to its geometric definition, helping shape its form. This fixed point is as crucial as the directrix in the parabolic structure.
For our exercise, the focus, along with the directrix \( y = 6 \), determines the orientation and direction of the parabola. With the vertex at the origin \( (0, 0) \) and a directrix at \( y = 6 \), the parabola opens downwards, positioning the focus at \( (0, -6) \).
For our exercise, the focus, along with the directrix \( y = 6 \), determines the orientation and direction of the parabola. With the vertex at the origin \( (0, 0) \) and a directrix at \( y = 6 \), the parabola opens downwards, positioning the focus at \( (0, -6) \).
- This position is because the parabola must be equidistant from the focus and the directrix.
- The distance between the vertex and the focus (\( p \)) is 6 units, calculated by taking half of the distance from the vertex to the directrix.
Conic Sections
Conic sections are curves obtained by slicing a cone at various angles. These include parabolas, ellipses, circles, and hyperbolas. Each type differs by the nature and angle of intersection.
Parabolas specifically arise when the cone is cut parallel to its side, leading to their distinctive U-shaped curve. Here are some key characteristics:
Parabolas specifically arise when the cone is cut parallel to its side, leading to their distinctive U-shaped curve. Here are some key characteristics:
- Symmetry around a central axis, which is aligned with their vertex.
- A unique relationship between every point on the curve with its focus and directrix.
Other exercises in this chapter
Problem 47
Find an equation for the hyperbola that satisfies the given conditions. Foci: \((0, \pm 3),\) hyperbola passes through \((1,4)\)
View solution Problem 47
Complete the square to determine whether the graph of the equation is an ellipse, a parabola, a hyperbola, or a degenerate conic. If the graph is an cllipse, fi
View solution Problem 48
Finding the Equation of an Ellipse Find an equation for the ellipse that satisfies the given conditions. Foci: \((\pm 5,0),\) length of major axis: 12
View solution Problem 48
Find an equation for the hyperbola that satisfies the given conditions. Foci: \((\pm \sqrt{10}, 0),\) hyperbola passes through \((4, \sqrt{18})\)
View solution