Problem 47
Question
Factor completely. $$10 x^{2}-40 x-600$$
Step-by-Step Solution
Verified Answer
The factorized form of the given equation is \(10(x -10)(x + 6)\)
1Step 1: Identify the Greatest Common Factor
Looking at the given quadratic equation \(10 x^{2}-40 x-600\), the common factors of 10, -40, and -600 is 10. Thus, we can factor out 10.
2Step 2: Factor Out the Greatest Common Factor
Factor out 10 from each term in the given equation. Doing this will result in \(10(x^{2} - 4x -60)\).
3Step 3: Factorize the Quadratic Equation
The quadratic equation \(x^{2} - 4x - 60\) can be factorized to \((x -10)(x + 6)\), using the fact that -4 is the sum of -10 and 6 and -60 is the product of -10 and 6.
4Step 4: Write the Final Answer
The factorization of the original equation is then given by substituting \((x -10)(x +6) \) back into the equation after factoring out 10, which results in \(10(x -10)(x +6)\)
Key Concepts
Greatest Common FactorQuadratic EquationFactoring Techniques
Greatest Common Factor
When factoring a polynomial, one of the first steps is to identify the greatest common factor (GCF) of all the terms. The GCF is the largest number or expression that divides all terms in the polynomial without leaving a remainder. For example, in the expression given:
To find the GCF, list the factors of each coefficient and variable, then choose the largest factor common to all terms.
In this example, each number is divisible by 10, and there are no variables common to all terms, hence it's factored as:
- 10 (\(x^2\)),
- -40 (x), and
- -600,
To find the GCF, list the factors of each coefficient and variable, then choose the largest factor common to all terms.
In this example, each number is divisible by 10, and there are no variables common to all terms, hence it's factored as:
- \(10x^2 - 40x - 600 = 10(x^2 - 4x - 60)\).
Quadratic Equation
A quadratic equation is one that involves a polynomial of degree 2, typically expressed in the form
For the equation
This transformation is possible if you can find two numbers that multiply to give the constant term
- $ax^2 + bx + c = 0$.
- $x^2 - 4x - 60 = 0$.
For the equation
- $x^2 - 4x - 60$,
This transformation is possible if you can find two numbers that multiply to give the constant term
- (-60)
- (-4).
Factoring Techniques
Factoring techniques are essential tools for simplifying polynomials and solving equations. In this exercise, we used a straightforward factoring technique known as the "zero product property" and trial and error to factor the quadratic.
Once we factor out the GCF and have the quadratic
These numbers are -10 and 6. Using these numbers, the quadratic
After factoring, you multiply back to ensure the product matches the original quadratic. This confirmation step verifies your factorization is correct, maintaining the integrity of the solution.
Once we factor out the GCF and have the quadratic
- $x^2 - 4x - 60$,
These numbers are -10 and 6. Using these numbers, the quadratic
- $x^2 - 4x - 60$
- (x - 10)(x + 6).
After factoring, you multiply back to ensure the product matches the original quadratic. This confirmation step verifies your factorization is correct, maintaining the integrity of the solution.
Other exercises in this chapter
Problem 46
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Now let's move on to factorizations that may require two or more techniques. Factor completely, or state that the polynomial is prime. Check factorizations usin
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Factor any perfect square trinomials, or state that the polynomial is prime. $$x^{2}-14 x+49$$
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