Problem 47
Question
Explain how you would solve the equation $$ \left(2^{x+1}\right)\left(8^{2 x-3}\right)=64 $$
Step-by-Step Solution
Verified Answer
The solution to the equation is \(x = 2\).
1Step 1: Express 8 and 64 as Powers of 2
First, we need to express all numbers in the equation in terms of powers of 2 for consistency. We know that \(8 = 2^3\) and \(64 = 2^6\). Thus, we can rewrite the equation as \((2^{x+1})(2^{3(2x-3)}) = 2^6\).
2Step 2: Simplify the Left Side of the Equation
Using the property of exponents \(a^m\cdot a^n = a^{m+n}\), simplify the left side of the equation. The first term \(2^{x+1}\) is \(2^x\cdot 2^1\). The second term \(2^{3(2x-3)}\) is \(2^{6x-9}\). Thus, we have \(2^{x+1 + 6x-9} = 2^6\).
3Step 3: Combine Exponents
Combine the exponents on the left side: \((x+1) + (6x-9)\) simplifies to \(7x - 8\). Therefore, the equation becomes \(2^{7x-8} = 2^6\).
4Step 4: Set Exponents Equal
Since the bases are the same, we can set the exponents equal to each other: \(7x - 8 = 6\). Solve this equation for \(x\).
5Step 5: Solve for x
Add 8 to both sides to obtain \(7x = 14\). Then, divide both sides by 7, resulting in \(x = 2\).
Key Concepts
Powers of 2Properties of ExponentsSolving EquationsStep-by-Step Solution
Powers of 2
Working with powers of 2 can greatly simplify solving exponential equations. In this problem, we deal with numbers like 8 and 64, which can be rewritten as powers of 2. This step is crucial because it transforms seemingly complex calculations into simpler operations that follow the rules of exponents.
- The number 8 can be expressed as \(8 = 2^3\).
- Similarly, 64 can be expressed as \(64 = 2^6\).
Properties of Exponents
Understanding the properties of exponents is essential for simplifying exponential expressions. These rules allow us to operate on expressions with the same base effectively. Two critical properties used in this exercise include:
- Product of Powers Property: When multiplying two exponents with the same base, like \(a^m\) and \(a^n\), you can simplify them by adding the exponents. The expression becomes \(a^{m+n}\).
- Power of a Power Property: When an exponent is raised to another exponent, such as \((a^m)^n\), you multiply the exponents: \(a^{m \cdot n}\).
Solving Equations
The process of solving exponential equations often involves making the equation look simpler by using the same base for all terms whenever possible. Here's a short guide on how to approach such problems:
- First, express all numbers as powers of a common base, such as 2 in our exercise.
- Then, simplify the left side using the properties of exponents by combining the exponents.
- With the equation simplified to a form \(2^a = 2^b\), set the exponents equal since they share the same base.
- Finally, solve the resulting linear equation for the variable.
Step-by-Step Solution
Providing a detailed step-by-step breakdown assists in breaking down the process into digestible parts:
- Step 1: Convert all terms to the same base, here powers of 2, transforming the given equation \((2^{x+1})(8^{2x-3}) = 64\) into \((2^{x+1})(2^{3(2x-3)}) = 2^6\).
- Step 2: Use the product of powers property to simplify the left side, resulting in \(2^{x+1+6x-9}\).
- Step 3: Combine and simplify the exponents to get \((x+1) + (6x-9) = 7x - 8\). The equation becomes \(2^{7x-8} = 2^6\).
- Step 4: Since the bases are the same on both sides, equate the exponents: \(7x - 8 = 6\).
- Step 5: Solve for \(x\) by isolating the variable. Add 8 to both sides to obtain \(7x = 14\), then divide by 7, resulting in \(x = 2\).
Other exercises in this chapter
Problem 47
(a) find \(f^{-1}\) and (b) verify that \(\left(f \circ f^{-1}\right)(x)=x\) and \(\left(f^{-1} \circ f\right)(x)=x\). $$ f(x)=x^{2}+4 \quad \text { for } x \ge
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How would you explain the concept of effective yield to someone who missed class when it was discussed?
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What rate of interest compounded continuously is needed for an investment of \(\$ 2500\) to grow to \(\$ 10,000\) in 20 years? \(6.9 \%\)
View solution Problem 48
Graph each of the functions. Remember that the graph of \(f(x)=\log _{2} x\) is given in Figure 10.27. $$ f(x)=-2+\log _{2} x $$
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