Problem 47
Question
Exer. \(47-50\) : Find an equation for the indicated half of the ellipse. $$\text { Left half of } \frac{x^{2}}{36}+\frac{y^{2}}{25}=1$$
Step-by-Step Solution
Verified Answer
Equation: \(\frac{x^2}{36} + \frac{y^2}{25} = 1\), with \(x \leq 0\).
1Step 1: Understand the Standard Form of an Ellipse
The given equation \(\frac{x^2}{36} + \frac{y^2}{25} = 1\) is in the standard form of an ellipse: \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\), where \(a^2 = 36\) and \(b^2 = 25\). This tells us the ellipse is centered at the origin \((0,0)\) and has a semi-major axis of length 6 along the x-axis and a semi-minor axis of length 5 along the y-axis.
2Step 2: Identify the Half of the Ellipse Required
We are asked to find the equation for the left half of the ellipse. The left half refers to the section of the ellipse where the x-values are negative, i.e., \(x \leq 0\).
3Step 3: Modify the Equation for the Left Half
To define only the left half, we keep the ellipse's equation as it is algebraically but restrict \(x\) to \(x \leq 0\). So, the equation for the left half of the ellipse is still \(\frac{x^2}{36} + \frac{y^2}{25} = 1\) with the condition \(x \leq 0\).
Key Concepts
half of an ellipseellipse centered at originstandard form of an ellipse
half of an ellipse
When dealing with ellipses, it's important to understand that an ellipse can be split into two halves. Either horizontally or vertically, based on its orientation. Looking at the given problem, we are interested in the 'left half' of the ellipse. Conceptually, this means focusing only on the part of the ellipse that exists on one side of the axis. In this exercise, the left half indicates that we will be considering the portion of the ellipse where all the x values are less than or equal to zero.
To find this part, we do not need to change the original equation. Instead, the focus is on restricting the x values by specifying a condition: **x ≤ 0**. This ensures that we only look at half of the shape.
To find this part, we do not need to change the original equation. Instead, the focus is on restricting the x values by specifying a condition: **x ≤ 0**. This ensures that we only look at half of the shape.
- The equation remains the same: \(\frac{x^2}{36} + \frac{y^2}{25} = 1\).
- However, remember: restrict to \(x \leq 0\).
ellipse centered at origin
An ellipse centered at the origin means that its center point is at the coordinate \(0,0\). This is an important aspect, as it simplifies our calculations and understanding of the shape's orientation and distribution. For the given exercise, the ellipse's equation \(\frac{x^2}{36} + \frac{y^2}{25} = 1\) confirms that the center is at the origin.
Ellipses centered at the origin are symmetrical about both the x-axis and y-axis. This fact makes it easier to identify and define halves of the ellipse. For example, in this scenario, identifying the left half simply involves considering the x values on the left side (negative side) of the y-axis. There is no need to visually adjust or move the shape as the symmetry around the origin helps with manipulation and understanding.
Ellipses centered at the origin are symmetrical about both the x-axis and y-axis. This fact makes it easier to identify and define halves of the ellipse. For example, in this scenario, identifying the left half simply involves considering the x values on the left side (negative side) of the y-axis. There is no need to visually adjust or move the shape as the symmetry around the origin helps with manipulation and understanding.
- Center of ellipse: \(0,0\)
- Symmetrical across both axes.
- Easy to describe sections, like the left half.
standard form of an ellipse
The standard form of an ellipse is a foundational concept in understanding and graphing these shapes. The ellipse's equation is given as \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\). Here, **a** and **b** represent the lengths of the semi-major and semi-minor axes respectively. For the equation \(\frac{x^2}{36} + \frac{y^2}{25} = 1\), this tells us several important things:
Understanding the standard form allows you to quickly derive key characteristics of any ellipse, such as orientation and axis lengths, which are vital in tasks like identifying halves or sections of the ellipse. The symmetry and simplicity of ellipses in their standard form make them manageable and predictable, especially when combined with an origin-centered positioning.
- \(a^2 = 36\), so \(a = 6\)
- \(b^2 = 25\), so \(b = 5\)
Understanding the standard form allows you to quickly derive key characteristics of any ellipse, such as orientation and axis lengths, which are vital in tasks like identifying halves or sections of the ellipse. The symmetry and simplicity of ellipses in their standard form make them manageable and predictable, especially when combined with an origin-centered positioning.
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