Problem 47
Question
Evaluate the flux integral \(\iint_{S} \mathbf{F} \cdot \mathbf{n} d S\) \(\mathbf{F}=\langle y, 0,2\rangle, S\) is the boundary of the region bounded above by \(z=\sqrt{8-x^{2}-y^{2}}\) and below by \(z=\sqrt{x^{2}+y^{2}}\) (n outward)
Step-by-Step Solution
Verified Answer
The flux integral is 0.
1Step 1: Setup of Flux Integral
Using divergence theorem, transform the flux integral into a triple integral. The divergence theorem states that \(\iint_{S} \mathbf{F} \cdot \mathbf{n} d S = \iiint_V (\nabla \cdot \mathbf{F}) dV\) where \(\nabla \cdot \mathbf{F}\) represents the divergence of \(\mathbf{F}\) and \(V\) is the region bounded by \(S\).
2Step 2: Compute the Divergence of \(\mathbf{F}\)
The divergence of \(\mathbf{F} = \langle y, 0,2\rangle\) is found by taking partial derivatives and adding them together. By doing this, find that \(\nabla \cdot \mathbf{F} = \frac{\partial}{\partial x}(y) + \frac{\partial}{\partial y}(0) + \frac{\partial}{\partial z}(2) = 0 + 0 + 0 = 0\).
3Step 3: Evaluating the Triple Integral
Given \(\nabla \cdot \mathbf{F} = 0\), this simplifies the triple integral to \(\iiint_V (\nabla \cdot \mathbf{F}) dV = 0\). Therefore, the original flux integral is also zero.
Key Concepts
Divergence TheoremTriple IntegralVector Calculus
Divergence Theorem
The Divergence Theorem is a fundamental principle in vector calculus that relates a surface integral of a vector field over a closed surface to a volume integral over the region bounded by the surface. It's a powerful tool that transforms a potentially complex flux integral into a simpler triple integral.
When considering the flux of a vector field \textbf{F} through a closed surface S, we are essentially measuring how much the field 'flows' out of the surface. Mathematically, this is given by the surface integral \(\iint_{S} \mathbf{F} \cdot \mathbf{n} dS\). Here, \(\mathbf{n}\) represents the outward-facing unit normal vector on the surface, and \(dS\) is an infinitesimal element of the surface area.
The Divergence Theorem states that this flux integral is equal to the volume integral of the divergence of \textbf{F} over the volume V enclosed by S:\[\iint_{S} \mathbf{F} \cdot \mathbf{n} dS = \iiint_V (abla \cdot \mathbf{F}) dV\]. The divergence, \(abla \cdot \mathbf{F}\), measures the rate at which the field is 'diverging' from each point, indicating sources or sinks within the volume.
To apply the theorem, one first computes the divergence of \(\mathbf{F}\), then sets up a triple integral over the volume V, and finally evaluates this triple integral to find the total flux across S. This method is particularly useful when the divergence is simpler to work with than the original vector field, or when the geometry of the surface makes the direct computation of the surface integral challenging.
When considering the flux of a vector field \textbf{F} through a closed surface S, we are essentially measuring how much the field 'flows' out of the surface. Mathematically, this is given by the surface integral \(\iint_{S} \mathbf{F} \cdot \mathbf{n} dS\). Here, \(\mathbf{n}\) represents the outward-facing unit normal vector on the surface, and \(dS\) is an infinitesimal element of the surface area.
The Divergence Theorem states that this flux integral is equal to the volume integral of the divergence of \textbf{F} over the volume V enclosed by S:\[\iint_{S} \mathbf{F} \cdot \mathbf{n} dS = \iiint_V (abla \cdot \mathbf{F}) dV\]. The divergence, \(abla \cdot \mathbf{F}\), measures the rate at which the field is 'diverging' from each point, indicating sources or sinks within the volume.
To apply the theorem, one first computes the divergence of \(\mathbf{F}\), then sets up a triple integral over the volume V, and finally evaluates this triple integral to find the total flux across S. This method is particularly useful when the divergence is simpler to work with than the original vector field, or when the geometry of the surface makes the direct computation of the surface integral challenging.
Triple Integral
A triple integral is an extension of double and single integrals to three dimensions, allowing for the calculation of volumes, masses, charges, and other properties over a three-dimensional region. For vector fields, as in the case of the flux integral, triple integrals become valuable for evaluating the total sum of a quantity throughout a volume.
Using Cartesian coordinates (x, y, z), a triple integral is expressed in the general form:\[\iiint_V f(x, y, z)\, dx\, dy\, dz\], where V is the volume of integration and f(x, y, z) is some function.
To solve a triple integral, you typically follow these steps:
Using Cartesian coordinates (x, y, z), a triple integral is expressed in the general form:\[\iiint_V f(x, y, z)\, dx\, dy\, dz\], where V is the volume of integration and f(x, y, z) is some function.
To solve a triple integral, you typically follow these steps:
- Identify the region of integration, V, which might be described by inequalities or boundaries.
- Decide on the order of integration (which variable to integrate first, second, and third), which is often informed by the symmetry of the region or the function.
- Set up the integral with the appropriate limits for each variable.
- Evaluate the integral, often by solving the innermost integral first and working outwards.
Vector Calculus
Vector calculus is an essential branch of mathematics for describing and analyzing multi-dimensional vector fields and their behaviors. It's a language that helps us interpret physical phenomena such as fluid flow, electromagnetic fields, and mechanical forces.
In our context, we are concerned with vector fields, which assign a vector to every point in space. For example, \(\mathbf{F} = \langle y, 0,2 \rangle\) gives the direction and magnitude of \(\mathbf{F}\) at each point. Such fields can represent, say, the velocity of fluid particles in flow or the strength of a magnetic field.
Core operations in vector calculus include:
In our context, we are concerned with vector fields, which assign a vector to every point in space. For example, \(\mathbf{F} = \langle y, 0,2 \rangle\) gives the direction and magnitude of \(\mathbf{F}\) at each point. Such fields can represent, say, the velocity of fluid particles in flow or the strength of a magnetic field.
Core operations in vector calculus include:
- Gradient (\(abla f\)) – measures the rate and direction of increase of a scalar field.
- Divergence (\(abla \cdot \mathbf{F}\)) – measures the magnitude of a source or sink at a given point in a vector field.
- Curl (\(abla \times \mathbf{F}\)) – measures the rotation or 'twisting' of a vector field.
Other exercises in this chapter
Problem 46
Use the notation \(r=\langle x, y\rangle\) and \(r=\|\mathbf{r}\|=\sqrt{x^{2}+y^{2}}\) $$\text { Show that } \nabla\left(r^{2}\right)=2 \mathbf{r}$$
View solution Problem 46
If \(T(x, y, t)\) is the temperature function at position \((x, y)\) at time \(t,\) heat flows across a curve \(C\) at a rate given by \(\oint_{C}(-k \nabla T)
View solution Problem 47
Use the notation \(r=\langle x, y\rangle\) and \(r=\|\mathbf{r}\|=\sqrt{x^{2}+y^{2}}\) $$\text { Find } \nabla\left(r^{3}\right)$$
View solution Problem 47
If \(f\) is a scalar function and \(\mathbf{F}\) a vector field, show that $$\nabla \cdot(f \mathbf{F})=\nabla f \cdot \mathbf{F}+f(\nabla \cdot \mathbf{F})$$
View solution