Problem 47
Question
Differentiable vector functions are continuous Show that if \(\mathbf{r}(t)=f(t) \mathbf{i}+g(t) \mathbf{j}+h(t) \mathbf{k}\) is differentiable at \(t=t_{0},\) then it is continuous at \(t_{0}\) as well.
Step-by-Step Solution
Verified Answer
Differentiability at \( t_0 \) implies \( \mathbf{r}(t) \) is continuous at \( t_0 \).
1Step 1: Define Differentiability
A vector function \( \mathbf{r}(t) = f(t) \mathbf{i} + g(t) \mathbf{j} + h(t) \mathbf{k} \) is differentiable at \( t = t_0 \) if the limit \[ \lim_{\Delta t \to 0} \frac{\mathbf{r}(t_0 + \Delta t) - \mathbf{r}(t_0)}{\Delta t} \] exists. Differentiability implies the existence of this limit.
2Step 2: Express Continuity
A vector function \( \mathbf{r}(t) \) is continuous at \( t=t_0 \) if \[ \lim_{t \to t_0} \mathbf{r}(t) = \mathbf{r}(t_0) \]. We need to show that if \( \mathbf{r}(t) \) is differentiable at \( t_0 \), this condition holds.
3Step 3: Analyze the Difference Quotient
Since \( \mathbf{r}(t) \) is differentiable at \( t = t_0 \), \[ \lim_{\Delta t \to 0} \frac{\mathbf{r}(t_0 + \Delta t) - \mathbf{r}(t_0)}{\Delta t} \] exists. This implies that \( \lim_{\Delta t \to 0} (\mathbf{r}(t_0 + \Delta t) - \mathbf{r}(t_0)) = 0 \).
4Step 4: Show the Limit Condition
From Step 3, since \( \lim_{\Delta t \to 0} (\mathbf{r}(t_0 + \Delta t) - \mathbf{r}(t_0)) = 0 \), it follows that \( \lim_{\Delta t \to 0} \mathbf{r}(t_0 + \Delta t) = \mathbf{r}(t_0) \). Thus, \( \mathbf{r}(t) \) is continuous at \( t = t_0 \).
Key Concepts
ContinuityExistence of LimitsDifference QuotientVector Calculus
Continuity
Continuity in vector functions means that the function behaves predictably without any abrupt changes at a given point. For a vector function \( \mathbf{r}(t) = f(t) \mathbf{i} + g(t) \mathbf{j} + h(t) \mathbf{k} \), continuity at a point \( t_0 \) implies that \\[ \lim_{t \to t_0} \mathbf{r}(t) = \mathbf{r}(t_0) \]This means as \( t \) gets closer to \( t_0 \), the output of the function approaches \( \mathbf{r}(t_0) \) closely. This predictable behavior ensures there are no jumps or gaps. Continuity is crucial because it ensures the function values change smoothly as the input values shift.
For a function to be continuous:
For a function to be continuous:
- The limit as \( t \to t_0 \) must exist.
- The value of the function at \( t_0 \) must be the same as this limit.
- The function behavior should exhibit no jumps, dips, or gaps at that point.
Existence of Limits
The existence of limits is a fundamental concept in calculus, crucial for understanding both differentiability and continuity. For a function to be differentiable at \( t_0 \), it must admit a limit as the interval approaches zero.
This is often expressed through:\[ \lim_{\Delta t \to 0} \frac{\mathbf{r}(t_0 + \Delta t) - \mathbf{r}(t_0)}{\Delta t} \]The existence of this limit confirms that the function's output behaves consistently and predictably as changes to the input become infinitesimally small.
If this limit exists, it also implies that:
This is often expressed through:\[ \lim_{\Delta t \to 0} \frac{\mathbf{r}(t_0 + \Delta t) - \mathbf{r}(t_0)}{\Delta t} \]The existence of this limit confirms that the function's output behaves consistently and predictably as changes to the input become infinitesimally small.
If this limit exists, it also implies that:
- Any small change in \( t \) around \( t_0 \) leads to a consistent small change in \( \mathbf{r}(t) \).
- The values of the function around \( t_0 \) do not deviate wildly but instead conform to a predictable pattern.
Difference Quotient
The difference quotient is an important tool used to compute the derivative of a vector function, acting as a bridge between basic algebra and calculus concepts. The difference quotient for a vector function \( \mathbf{r}(t) \) is expressed as:\[ \frac{\mathbf{r}(t_0 + \Delta t) - \mathbf{r}(t_0)}{\Delta t} \]This quotient gives an average rate of change over the interval \( \Delta t \).
When the interval \( \Delta t \) approaches zero, the difference quotient morphs into the derivative, provided the limit exists.
This transition from average to instantaneous change highlights the essence of calculus:
When the interval \( \Delta t \) approaches zero, the difference quotient morphs into the derivative, provided the limit exists.
This transition from average to instantaneous change highlights the essence of calculus:
- Calculating the velocity of a particle when \( \mathbf{r}(t) \) represents position over time.
- Predicting the behavior of physical systems in engineering and physics.
- Smoothing out real-life applications where tracking changes becomes essential.
Vector Calculus
Vector calculus extends traditional calculus into the realm of multi-dimensional processes, utilizing vectors to explore complex systems. Unlike scalar calculus, which deals with quantities described by single values, vector calculus takes into account both magnitude and direction.
In the context of differentiable vector functions, we express these functions in vector form as:\[ \mathbf{r}(t) = f(t) \mathbf{i} + g(t) \mathbf{j} + h(t) \mathbf{k} \]These functions harness the power of vector fields, helpful in fields such as physics (e.g., electromagnetism), engineering, and computer graphics. By understanding and implementing vector calculus:
In the context of differentiable vector functions, we express these functions in vector form as:\[ \mathbf{r}(t) = f(t) \mathbf{i} + g(t) \mathbf{j} + h(t) \mathbf{k} \]These functions harness the power of vector fields, helpful in fields such as physics (e.g., electromagnetism), engineering, and computer graphics. By understanding and implementing vector calculus:
- We can formulate methods for describing and predicting the behavior of 3D objects.
- We can effectively manage systems where directionality and magnitude are core factors.
- It provides tools to navigate and solve complex problems requiring multidimensional reasoning.
Other exercises in this chapter
Problem 45
Component test for continuity at a point Show that the vector function \(r\) defined by \(\mathbf{r}(t)=f(t) \mathbf{i}+g(t) \mathbf{j}+h(t) \mathbf{k}\) is con
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