Problem 47
Question
A boy released a ball from the top of a building. It will clear a window \(2 \mathrm{~m}\) high at a distance \(10 \mathrm{~m}\) below the top in nearly (a) \(1 \mathrm{~s}\) (b) \(1.3 \mathrm{~s}\) (c) \(0.6 \mathrm{~s}\) (d) \(0.13 \mathrm{~s}\)
Step-by-Step Solution
Verified Answer
The ball clears the window in 1.3 seconds (option b).
1Step 1: Understand the Problem
A ball is released from rest, and the task is to calculate the time it takes for the ball to clear a window located 10 meters below the top of the building. The height of the window is 2 meters.
2Step 2: Use the Kinematic Equation
We need to use the kinematic equation for an object initially at rest under the influence of gravity: \( h = \frac{1}{2} g t^2 \). Here, \( h \) is the vertical distance (10 m), and \( g \) is the acceleration due to gravity (approximately 9.81 m/s²).
3Step 3: Solve for Time
Substitute the known values into the equation: \( 10 = \frac{1}{2} \times 9.81 \times t^2 \). Solving for \( t \): \[ t^2 = \frac{10 \times 2}{9.81} \]\[ t = \sqrt{\frac{20}{9.81}} \]
4Step 4: Calculate the Time
Perform the calculations: \[ t = \sqrt{\frac{20}{9.81}} \approx 1.43 \text{ s} \]
5Step 5: Choose the Closest Option
Comparing the calculated time 1.43 s with the given options, the nearest choice is (b) 1.3 s.
Key Concepts
Kinematic EquationsAcceleration due to GravityFree Fall
Kinematic Equations
Kinematic equations are fundamental tools in physics that describe the motion of objects. They are particularly useful when analyzing projectile motion, like in the case of a ball in free fall. Kinematic equations relate several key parameters of motion: initial velocity, final velocity, acceleration, time, and displacement. For an object starting from rest under constant acceleration, like gravity, the main equation we often use is: \[ h = \frac{1}{2} g t^2 \]Here,
- \( h \) is the displacement or height the object travels,
- \( g \) is the acceleration due to gravity,
- and \( t \) is the time elapsed.
Acceleration due to Gravity
Gravity is a universal force that attracts two bodies towards one another. On Earth, it provides a constant acceleration to objects in free fall. This acceleration due to gravity, denoted as \( g \), is approximately \( 9.81 \, \text{m/s}^2 \) near the Earth's surface.This constant value means that any object in free fall, regardless of its mass, will experience the same acceleration.
- This principle simplifies many projectile motion problems.
- We assume that air resistance is negligible, focusing purely on gravitational effects.
Free Fall
Free fall describes the motion of an object under the influence of gravitational force only. An object in free fall experiences constant acceleration due to gravity, with no other forces acting upon it.When a ball is released, like in our exercise, it enters a state of free fall. Key aspects of free fall include:
- Constant acceleration: The only acceleration is due to gravity, \( g = 9.81 \, \text{m/s}^2 \).
- Initial velocity is zero when dropped: The ball starts from rest.
- Increasing velocity: As time progresses, the velocity of the falling ball increases linearly because of the constant acceleration.
Other exercises in this chapter
Problem 46
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