Problem 46
Question
Write your answer as a power or as a product of powers. $$ \left(5 b^{2}\right)^{3}\left(\frac{1}{2} b^{3}\right)^{2} $$
Step-by-Step Solution
Verified Answer
The simplified answer in terms of powers is \(31.25*b^{12}\)
1Step 1: Applying power of a power property
Start by applying the power of a power property, which gives \((5^3) * (b^{2*3}) = 125 * b^6\). Similarly, apply this rule to the next bracket yielding \((\(\frac{1}{2}\)^2 * b^{3*2}) = \(\frac{1}{4}\) * b^6\)
2Step 2: Applying power of a product property
Now use the power of a product property to multiply both results. This results in \(125*b^6 * \(\frac{1}{4}\)*b^6 = (125*\(\frac{1}{4}\)) * b^{6 + 6} = 31.25*b^{12}\)
3Step 3: Final simplification
After simplifying, the expression is reduced to \(31.25*b^{12}\)
Key Concepts
Power of a Power PropertyPower of a Product PropertySimplifying Expressions
Power of a Power Property
When dealing with exponents, the power of a power property is incredibly helpful for simplification. This property states that when you raise a power to another power, you multiply the exponents. For example, if you have
In the exercise, we applied this property to both
- \( (a^m)^n \)
In the exercise, we applied this property to both
- \( (5 b^{2})^{3} \)
- \( \left(\frac{1}{2} b^{3}\right)^{2} \)
- \( b^{2} \) raised to \( 3 \) as \( b^{2 \times 3} = b^6 \)
- \( b^{3} \) raised to \( 2 \) as \( b^{3 \times 2} = b^6 \)
Power of a Product Property
Power of a product property comes in handy when dealing with an expression that includes a product being raised to a power. This property allows you to apply the exponent to each factor within the parentheses separately. As a formula, it can be written as:
- \( (ab)^n = a^n \cdot b^n \)
- \( (5b^{2})^{3} \)
- \( (\frac{1}{2}b^{3})^{2} \)
- \( 5^3 \cdot b^6 \)
- \( (\frac{1}{2})^2 \cdot b^6 \)
Simplifying Expressions
Simplifying expressions is an essential skill in algebra allowing complex expressions to be reduced into simpler forms. In the exercise, we combined the previous steps to ultimately simplify the initial expression.
- First, by multiplying the numeric values: \( 125 \times \frac{1}{4} = 31.25 \)
- Next, by applying the properties of exponents on like terms, \( b^{6+6} = b^{12} \)
Other exercises in this chapter
Problem 45
Solve the equation. $$-2(7-5 x)=10$$
View solution Problem 45
EVALUATING EXPRESSIONS Evaluate the expression without using a calculator. Write the result in scientific notation and in decimal form. $$ \left(9 \times 10^{3}
View solution Problem 46
Simplify the expression. The simplified expression should have no negative exponents. $$ \frac{6 x^{-2} y^{2}}{x y^{-3}} \cdot \frac{\left(4 x^{2} y\right)^{-2}
View solution Problem 46
Solve the equation. Round the result to the nearest tenth if necessary. $$-1.3 y+3.7=4.2-5.4 y$$
View solution