Problem 46
Question
Write expression in terms of sine and cosine, and simplify it. (The final expression does not have to be in terms of sine and cosine.) $$\frac{1}{1+\cot ^{2} \theta}$$
Step-by-Step Solution
Verified Answer
The simplified expression is \( \sin^2 \theta \).
1Step 1: Understand the Cotangent Identity
Recall that \( \cot \theta = \frac{1}{\tan \theta} \), which can be written in terms of sine and cosine as \( \cot \theta = \frac{\cos \theta}{\sin \theta} \). Therefore, \( \cot^2 \theta = \left( \frac{\cos \theta}{\sin \theta} \right)^2 = \frac{\cos^2 \theta}{\sin^2 \theta} \).
2Step 2: Use the Pythagorean Identity
The Pythagorean identity states that \( 1 + \tan^2 \theta = \sec^2 \theta \) or alternatively, using division, that \( \tan^2 \theta + 1 = \sec^2 \theta \). We are rewriting in terms of \( \cot \theta \) therefore the identity \( 1 + \cot^2 \theta = \csc^2 \theta \) (since \( \csc \theta = \frac{1}{\sin \theta} \)).Using this identity, \( 1 + \cot^2 \theta = \frac{1}{\sin^2 \theta} \).
3Step 3: Substitute the Identity into the Expression
Substitute the result from Step 2 into the given expression:\[ \frac{1}{1 + \cot^2 \theta} = \frac{1}{\csc^2 \theta} = \sin^2 \theta \].
4Step 4: Final Step: Simplify
Thus, the simplified expression in terms of sine is \( \sin^2 \theta \). Since there is no further simplification possible beyond this point, the expression can remain as \( \sin^2 \theta \).
Key Concepts
CotangentPythagorean IdentitySine and Cosine
Cotangent
The cotangent function is one of the fundamental trigonometric functions, and it is closely connected to the tangent function. While the tangent of an angle \( \theta \) is the ratio of the sine to the cosine, the cotangent is its reciprocal. In mathematical terms, the cotangent of \( \theta \) is expressed as:
- \( \cot \theta = \frac{1}{\tan \theta} \)
- This can also be written in terms of sine and cosine as \( \cot \theta = \frac{\cos \theta}{\sin \theta} \)
Pythagorean Identity
The Pythagorean Identity is a key cornerstone in trigonometry, often used to simplify expressions. It stems from the Pythagorean theorem that applies to right-angled triangles but is adapted for trigonometric purposes. The identity in its most common form is:
- \( \sin^2 \theta + \cos^2 \theta = 1 \)
- \( \csc \theta \), the cosecant, is the reciprocal of sine, expressed as \( \csc \theta = \frac{1}{\sin \theta} \)
Sine and Cosine
Sine and cosine are the foundational pillars of trigonometry. Understanding these functions is vital for solving a wide range of trigonometric problems. Here’s a brief overview:
- Sine: Represented as \( \sin \theta \), it is the opposite side over the hypotenuse in a right triangle.
- Cosine: Denoted as \( \cos \theta \), it is the ratio of the adjacent side to the hypotenuse.
- Express \( \cot^2 \theta \) as \( \frac{\cos^2 \theta}{\sin^2 \theta} \)
- Utilize the identity to transform \( 1 + \cot^2 \theta \) into \( \csc^2 \theta \)
- The final simplification results in \( \sin^2 \theta \)
Other exercises in this chapter
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