Problem 46
Question
Write each of the following in terms of \(i\), perform the indicated operations, and simplify. $$ \sqrt{-7} \sqrt{-10} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \(-\sqrt{70}\).
1Step 1: Express Each Root in Terms of i
Both \(\sqrt{-7}\) and \(\sqrt{-10}\) involve the square root of a negative number. We know that \( \sqrt{-1} = i \). Therefore, \( \sqrt{-7} = \sqrt{7} \cdot i \) and \( \sqrt{-10} = \sqrt{10} \cdot i \).
2Step 2: Multiply the Expressions
Multiply the expressions \( \sqrt{7} \cdot i \) and \( \sqrt{10} \cdot i \) together. This gives us: \( (\sqrt{7} \cdot i) \cdot (\sqrt{10} \cdot i) = \sqrt{7} \sqrt{10} \cdot i^2 \).
3Step 3: Simplify the Expression
Simplify \(\sqrt{7} \sqrt{10} \cdot i^2\). We know that \(i^2 = -1\), so the expression becomes \(-\sqrt{7} \cdot \sqrt{10}\).
4Step 4: Final Simplification
Calculate \(\sqrt{7} \cdot \sqrt{10}\) which results in \(\sqrt{70}\). Thus, the expression simplifies to \(-\sqrt{70}\).
Key Concepts
Imaginary UnitSquare Roots of Negative NumbersComplex Multiplication
Imaginary Unit
When we talk about the imaginary unit, we're referring to a very special number in mathematics denoted as \(i\). It represents the square root of \(-1\).
This concept is crucial because, in the real number system, taking the square root of a negative number is not possible.
The imaginary unit \(i\) allows us to extend numbers beyond the real line into what we call the complex plane. Here are some key points about the imaginary unit:
This concept is crucial because, in the real number system, taking the square root of a negative number is not possible.
The imaginary unit \(i\) allows us to extend numbers beyond the real line into what we call the complex plane. Here are some key points about the imaginary unit:
- The fundamental property of \(i\) is that \(i^2 = -1\).
- It enables us to express square roots of negative numbers in terms of real numbers and \(i\). For example, \(\sqrt{-4}\) is written as \(2i\) since \(\sqrt{4} = 2\) and \(\sqrt{-1} = i\).
- Complex numbers are written in the form \(a + bi\), where \(a\) and \(b\) are real numbers. In this sense, \(i\) acts like a coordinate showing the position on the imaginary axis.
Square Roots of Negative Numbers
Finding square roots of negative numbers might seem unusual because normal arithmetic with real numbers doesn't support it. However, the imaginary unit \(i\) allows us to handle this. Here's how it works:When you face the square root of a negative number \(\sqrt{-x}\) (where \(x\) is positive), you would express it using the imaginary unit:\[\sqrt{-x} = \sqrt{x} \cdot i\]
This expression breaks down the problem into the familiar square root of a positive number and the square root of \(-1\), symbolized by \(i\).What does this achieve? It transforms a non-real number into something we can work with mathematically:
This expression breaks down the problem into the familiar square root of a positive number and the square root of \(-1\), symbolized by \(i\).What does this achieve? It transforms a non-real number into something we can work with mathematically:
- The square root of a negative number becomes manageable and fits within the structure of complex numbers.
- This transformation helps perform operations by using the property \(i^2 = -1\) to simplify further calculations.
- By breaking down \(\sqrt{-7}\) and \(\sqrt{-10}\) into \(\sqrt{7} \cdot i\) and \(\sqrt{10} \cdot i\), we can proceed with multiplication and simplification.
Complex Multiplication
Complex multiplication involves multiplying numbers that include the imaginary unit \(i\). This technique is similar in concept to multiplying polynomials, where you multiply coefficients and follow distribution across terms.To multiply two complex numbers or expressions like \(\sqrt{7} \cdot i\) and \(\sqrt{10} \cdot i\) from our problem, you follow these steps:
- Multiply the numerical (real) parts together. Here, it's \(\sqrt{7} \cdot \sqrt{10}\), which results in \(\sqrt{70}\).
- Multiply the imaginary units \(i \cdot i\) to apply the property \(i^2 = -1\).
- The combination \((\sqrt{7} \cdot i) \cdot (\sqrt{10} \cdot i)\) simplifies to \(\sqrt{70} \cdot i^2\), which further reduces to \(-\sqrt{70}\).
Other exercises in this chapter
Problem 46
Set up an equation and solve each problem. Find two numbers such that their sum is 6 and their product is 7 .
View solution Problem 46
Solve each quadratic equation using the method that seems most appropriate. $$ (x-3)(x+5)=-7 $$
View solution Problem 47
Solve each inequality. $$ \frac{2 x}{x+3}>4 $$
View solution Problem 47
Set up an equation and solve each problem. Suppose that the sum of two whole numbers is 9 , and the sum of their reciprocals is \(\frac{1}{2}\). Find the number
View solution