Problem 46
Question
When excess of dilute \(\mathrm{NH}_{4} \mathrm{OH}\) is added to an aqueous solution of \(\mathrm{CuSO}_{4}\) an intense blue colour is obtained. This blue colour is due to the presence of (a) \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\) (b) \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}\) (c) \(\mathrm{CuSO}_{4}\) (d) \(\mathrm{Cu}(\mathrm{OH})_{2}\)
Step-by-Step Solution
Verified Answer
(a) The blue color is due to the [Cu(NH3)4]^{2+} complex ion.
1Step 1: Reactants Identification
Identify the chemical species involved in the reaction. We have aqueous copper sulfate (CuSO4) and ammonium hydroxide (NH4OH). Upon adding excess NH4OH, the transition metal copper forms a complex.
2Step 2: Complex Formation
Understand that copper can form coordination complexes. When NH4OH is added to CuSO4, the copper ions react with ammonia (NH3) from the dissociation of NH4OH creating a complex with intense blue color.
3Step 3: Write Chemical Equation
Write the balanced chemical equation for the complex formation:\[\text{Cu}^{2+} + 4 \text{NH}_3 \rightleftharpoons [\text{Cu(NH}_3{)}_4]^{2+}\]This represents the formation of tetraamminecopper(II) ion.
4Step 4: Identify Color Source
The intense blue color is due to the [Cu(NH3)4]^{2+} complex ion which is known for its blue color in solution.
5Step 5: Choose Correct Option
From the given options, the intense blue color is caused by the [Cu(NH3)4]^{2+} complex, matching option (a).
Key Concepts
Complex Ion FormationTetraamminecopper(II) IonTransition Metal Chemistry
Complex Ion Formation
Complex ion formation involves the combination of a central metal ion with ligands, which are molecules or ions that can donate a pair of electrons to form a coordinate covalent bond. This process is significant in chemistry, particularly when dealing with transition metals. Upon the reaction of aqueous copper sulfate (\( ext{CuSO}_4 \)) with ammonium hydroxide (\( ext{NH}_4 ext{OH} \)), copper ions (\( ext{Cu}^{2+} \)) interact with ammonia (\( ext{NH}_3 \)) molecules, resulting in a coordination complex.
In forming these complex ions, the metal serves as the Lewis acid, meaning it accepts electron pairs. The ligands, on the other hand, act as Lewis bases by donating electron pairs. This interaction leads to the formation of a stable complex ion. These interactions are essential not only in explaining the vivid colors associated with metal solutions but also in various biological and industrial processes.
Some important points about complex ions include:
In forming these complex ions, the metal serves as the Lewis acid, meaning it accepts electron pairs. The ligands, on the other hand, act as Lewis bases by donating electron pairs. This interaction leads to the formation of a stable complex ion. These interactions are essential not only in explaining the vivid colors associated with metal solutions but also in various biological and industrial processes.
Some important points about complex ions include:
- They can involve different geometries depending on the number and type of ligands.
- The strength and color of these complexes can change based on the ligands involved.
Tetraamminecopper(II) Ion
The tetraamminecopper(II) ion, represented as \( [\text{Cu(NH}_3)_4]^{2+} \), is formed when copper ions (\( ext{Cu}^{2+} \)) are bound to four ammonia (\( ext{NH}_3 \)) molecules. This specific ion is responsible for the striking deep blue coloration seen in an aqueous solution.
The creation of \( [\text{Cu(NH}_3)_4]^{2+} \) occurs when excess ammonia is introduced to copper sulfate, prompting a series of reactions:
The creation of \( [\text{Cu(NH}_3)_4]^{2+} \) occurs when excess ammonia is introduced to copper sulfate, prompting a series of reactions:
- The copper ion in the solution reacts with ammonia, which acts as a ligand by donating electron pairs.
- Four ammonia molecules surround the copper ion, leading to a stable four-coordinate complex.
- This complex is what gives the solution its intense blue hue, distinguishing it from other potential reactions.
Transition Metal Chemistry
Transition metal chemistry is a fascinating area of study due to the unique properties of transition metals in forming complex ions and coordination compounds. Transition metals, such as copper in the \( ext{CuSO}_4 \) solution, often have multiple oxidation states and the ability to form various complex geometries.
One of the distinctive features of transition metals is their ability to produce colored compounds. This is due to specific electron transfers between d-orbitals when ligands form coordinate bonds with the metal ions. In the case of tetramminecopper(II) ion formation, the complexing process introduces a new arrangement of electrons, leading to its observed color.
Key characteristics of transition metal chemistry include:
One of the distinctive features of transition metals is their ability to produce colored compounds. This is due to specific electron transfers between d-orbitals when ligands form coordinate bonds with the metal ions. In the case of tetramminecopper(II) ion formation, the complexing process introduces a new arrangement of electrons, leading to its observed color.
Key characteristics of transition metal chemistry include:
- Variable oxidation states allowing diverse chemical behavior.
- Formation of colored ions due to electron d-d transitions.
- Ability to form stable complexes, which have significant roles in catalysis and biological systems.
Other exercises in this chapter
Problem 43
What is formed when \(\mathrm{H}_{2} \mathrm{~S}\) is passed through acidified solution of \(\mathrm{CuSO}_{4}\) ? (a) \(\mathrm{CuSO}_{4}\) (b) \(\mathrm{CuS}\
View solution Problem 44
What is produced when cuprous oxide reacts with HCl? (a) \(\mathrm{CuCl}\) (b) \(\mathrm{CuO}\) (c) \(\mathrm{HCuCl}_{2}\) (d) \(\mathrm{CuCl}_{2}\)
View solution Problem 47
Which of the following is formed when cupric oxide reacts with glucose? (a) \(\mathrm{CuCHO}\) (b) \(\mathrm{CuO}\) (c) \(\mathrm{Cu}_{2} \mathrm{O}\) (d) \(\ma
View solution Problem 48
Copper forms nitrogen oxide with dilute nitric acid but with concentrated nitric acid it gives (a) nitrogen dioxide (b) nitrogen oxide (c) nitrogen peroxide (d)
View solution