Problem 46
Question
When excess of dilute \(\mathrm{NH}_{4} \mathrm{OH}\) is added to an aqueous solution of \(\mathrm{CuSO}_{4}\) an intense blue colour is obtained. This blue colour is due to the presence of (a) \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\) (b) \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}\) (c) \(\mathrm{CuSO}_{4}\) (d) \(\mathrm{Cu}(\mathrm{OH})_{2}\)
Step-by-Step Solution
Verified Answer
The blue color is due to \([\mathrm{Cu}(\mathrm{NH}_3)_4]^{2+}\), so the answer is (a).
1Step 1: Identify the Reaction Involved
When \(\mathrm{NH}_{4} \mathrm{OH}\) is added to \(\mathrm{CuSO}_{4}\), an important chemical reaction occurs between ammonia, \(\mathrm{NH}_{3}\), and copper ions, \(\mathrm{Cu}^{2+}\), to form a complex ion.
2Step 2: Determine the Complex Ion
When ammonia is added to the aqueous \(\mathrm{CuSO}_{4}\) solution, \(\mathrm{Cu}^{2+}\) ions react with \(\mathrm{NH}_{3}\) molecules to form the complex ion \[\left[ \mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\]. This complex is responsible for the intense blue color.
3Step 3: Determine the Correct Option
Match the complex ion responsible for the blue color to the given options. Option (a) \[\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\]\ is the correct ion that causes the blue color.
Key Concepts
Complex Ion FormationAmmonia ComplexesCopper-Ammonia ComplexChemical Reactions
Complex Ion Formation
Complex ion formation is a fascinating area of chemistry where metal ions bond with molecules or ions, known as ligands, to form complex ions. This process is essential in understanding many chemical reactions in coordination chemistry. When a metal ion, such as copper (\(\text{Cu}^{2+}\)), encounters ammonia (\(\text{NH}_3\)) in a solution, the ammonia molecules act as ligands. They donate electron pairs to the metal ion, forming a coordinate covalent bond.
- This interaction leads to the creation of a new species, the complex ion.
- Complex ions often exhibit distinct colors, resulting from electronic transitions within the partly filled d-orbitals of metal ions.
Ammonia Complexes
Ammonia complexes are significant examples of complex ions where ammonia, a small molecule with a lone pair of electrons on the nitrogen atom, acts as a ligand. It can easily coordinate with transition metal ions due to its ability to donate an electron pair.
Ammonia complexes are particularly well-known because they demonstrate spectacular changes in the properties of solutions, such as color:
- Ammonia ligands replace water molecules around a metal ion, altering the electronic properties of the metal center.
- This substitution often results in the appearance of vibrant colors, exemplifying the dramatic effect ligands can have on complex ions.
Copper-Ammonia Complex
The copper-ammonia complex is a classic case illustrating the formation and properties of complex ions. When copper sulfate (\(\text{CuSO}_4\)) dissolves in water, it produces \(\text{Cu}^{2+}\) ions. Upon the addition of ammonia, these \(\text{Cu}^{2+}\) ions interact with ammonia molecules to form the copper-ammonia complex ion, \(\left[ \text{Cu}\left(\text{NH}_3\right)_4\right]^{2+}\).This complex ion is responsible for an intense blue color due to the ligand ammonia altering the copper ion's electronic structure:
- The \(\text{d}\)-orbital splitting and electron transitions within these orbitals cause the characteristic blue hue.
- This reaction showcases how ligand binding can impact the visual and chemical behavior of metal ions.
Chemical Reactions
Chemical reactions involve the transformation of substances through the breaking and making of chemical bonds, often resulting in new products with distinct properties. The reaction between ammonia and copper sulfate is a classic example showcasing complex formation:
- In this case, \(\text{NH}_3\) molecules in solution react with \(\text{Cu}^{2+}\) ions.
- This results in the formation of the complex ion \(\left[ \text{Cu}\left(\text{NH}_3\right)_4\right]^{2+}\), responsible for the characteristic blue color seen in the solution.
Other exercises in this chapter
Problem 43
What is formed when \(\mathrm{H}_{2} \mathrm{~S}\) is passed through acidified solution of \(\mathrm{CuSO}_{4}\) ? (a) \(\mathrm{CuSO}_{4}\) (b) \(\overline{\ma
View solution Problem 44
What is produced when cuprous oxide reacts with HCl? (a) \(\mathrm{CuCl}\) (b) \(\mathrm{CuO}\) (c) \(\mathrm{HCuCl}_{2}\) (d) \(\mathrm{CuCl}_{2}\)
View solution Problem 47
Which of the following is formed when cupric oxide reacts with glucose? (a) \(\mathrm{CuCHO}\) (b) \(\mathrm{CuO}\) (c) \(\mathrm{Cu}_{2} \mathrm{O}\) (d) \(\ma
View solution Problem 49
The white anhydrous copper sulphate decomposes to give (a) \(\mathrm{CuO}+\mathrm{SO}_{3}\) (b) \(\mathrm{Cu}\) (c) \(\mathrm{CuSO}_{4} \cdot \mathrm{H}_{2} \ma
View solution